riseofphoenix
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Why is the answer to this period?
I know
T = 2π√(L/g)
But I don't know how period doesn't change if you double amplitude, when amplitude isn't even in the equation (?)
The discussion centers on the relationship between amplitude and period in the context of simple harmonic motion, specifically using the formula T = 2π√(L/g). Participants clarify that the period (T) of a pendulum is independent of amplitude, as amplitude does not appear in the equation. This indicates that doubling the amplitude does not affect the period, reinforcing the principle that the period is solely determined by the length of the pendulum (L) and the acceleration due to gravity (g).
PREREQUISITESStudents of physics, educators teaching mechanics, and anyone interested in the principles of pendulum motion and simple harmonic oscillators.
Perhaps the fact that amplitude is not in this formula for period means that the period does not depend upon the amplitude.riseofphoenix said:![]()
Why is the answer to this period?
I know
T = 2π√(L/g)
But I don't know how period doesn't change if you double amplitude, when amplitude isn't even in the equation (?)