Which Photon Energy Can Overcome a 3.00 eV Work Function?

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Homework Help Overview

The discussion revolves around the photoelectric effect, specifically determining the minimum photon energy required to overcome a work function of 3.00 eV for photoelectron production. Participants are examining various photon energy options to identify which can result in the emission of photoelectrons.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are exploring the relationship between photon energy, work function, and kinetic energy. Questions arise about the definitions of terms in the relevant equation and the conditions necessary for photoelectron production.

Discussion Status

Some participants are attempting to clarify their understanding of the photoelectric effect and the significance of the work function. There is a mix of interpretations regarding the energy levels required for photoelectron emission, with some guidance provided on how to approach the problem.

Contextual Notes

Participants express uncertainty about the concept of kinetic energy in relation to the work function and photon energy. The discussion includes references to textbook material and the need for further review of the photoelectric effect.

sgoeke
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Homework Statement



Of the following energies for photons, which is the least energy that could result in photoeletron production if the work function is 3.00 eV?
a. 1.50 eV
b. 2.90 eV
c. 3.50 eV
d. 6.01 eV

Homework Equations



KE = E - W

The Attempt at a Solution



I don't know where to go with this. please help!
 
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sgoeke said:
KE = E - W
What do the three terms in this equation stand for? Which ones can be identified with what is given?
 
KE is the kinetic energy, E is the energy of the photon (E=hf or E=hc/lambda), and W is the work function. 3 eV is the work function (W). We're looking for E. But I don't know what KE would be.
 
sgoeke said:
KE is the kinetic energy, E is the energy of the photon (E=hf or E=hc/lambda), and W is the work function. 3 eV is the work function (W). We're looking for E. But I don't know what KE would be.
No you don't. Go down the list of possible answers starting with (a). Would a 1.50 eV photon produce a photoelectron? If so, what would would the photoelectron's KE be?
 
How do you know you produce a photoelectron?
 
sgoeke said:
How do you know you produce a photoelectron?
Can a 1.50 eV photon produce a photoelectron if the work function is 3.0 eV? The answer is "yes" or "no". If you don't know how to answer this question then you do not understand the photoelectric effect, specifically what "work function" means. You need to review the photoelectric effect by reading your textbook or getting on the web. If you are still confused, explain what you do understand and what you don't and someone will help you.
 
The KE depends on the light frequency and the critical frequency is the photons whose energy is equal to the work funciton. I guess I'm really not making the connection for this problem even after reading this section of my textbook multiple times.
 
The idea behind the photoelectric effect is very simple. Think of energy as money. The work function is the exit fee that an electron has to pay to leave the metal. A photon comes along and gives all the money it has to an electron in the metal. Two things may happen as a result.
1. If the electron has more money than the exit fee, it pays it, leaves the metal and takes with it the change as kinetic energy.
2. If the electron does not have enough money to pay the exit fee, it stays where it is and the photon's money is shared in some fashion within the metal.

Now again, can you answer the question "Can a 1.50 eV photon produce a photoelectron if the work function is 3.0 eV?"
 
So the energy would need to be larger than the work function? So the least amount of energy for the ones given would be 3.5?
 
  • #10
sgoeke said:
So the energy would need to be larger than the work function? So the least amount of energy for the ones given would be 3.5?
Bingo! :biggrin:
 
  • #11
Thanks...that really really helped!
 

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