Which solution is correct (Tension)

  • Thread starter SheldonG
  • Start date
  • #1
SheldonG
50
0

Homework Statement


A section of a cable car system, showing three cars. They are being pulled by drag cables at 35 degrees above the horizontal. Each car weighs 2800 kg. The are all being accelerated at the same rate of 0.81 m/s/s. The problem asks for the difference between the tensions in the two cables that connect to the middle car.


Homework Equations


F=ma


The Attempt at a Solution



Solution 1:

I started by writing the force equations in X and Y:

Fy = ma sin 35 = T sin 35 - mg
Fx = ma cos 35 = T2 cos 35 - T1 cos 35

Obviously, I don't need the Fy equation at all, since the cos 35 drops out and I have:

ma = T2- T1

Then I thought to try solving it by having the X axis along the 35 degree line of the cables. This gives me:

Fx = ma = T1 - mg sin 35 - T2

with T1 - T2 = m(a + g sin 35)

They both give very different results, and both seem reasonable to me. I have no idea which one is correct or why. If someone could help me out, I would appreciate it.

Thanks,
Sheldon
 
Last edited:

Answers and Replies

  • #2
alphysicist
Homework Helper
2,238
2
Hi SheldonG,

This one is correct:

Then I thought to try solving it by having the X axis along the 35 degree line of the cables. This gives me:

Fx = ma = T1 - mg sin 35 - T2

with T1 - T2 = m(a + g sin 35)


The reason the first one is not correct is that there is a normal force on the cable car, perpendicular to the cable. With your axes chosen as they were in method 1, the components of this force would need to be included. But for method 2, the normal force had not component along the cable, so it was not needed.
 
  • #3
SheldonG
50
0
Many thanks!
 

Suggested for: Which solution is correct (Tension)

Replies
2
Views
106
Replies
6
Views
834
  • Last Post
Replies
14
Views
492
  • Last Post
Replies
27
Views
585
  • Last Post
Replies
25
Views
958
  • Last Post
Replies
3
Views
361
  • Last Post
Replies
3
Views
275
  • Last Post
Replies
2
Views
273
Top