Whirling a Ball on a String: Vmin & Vmax Explained

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In the discussion about whirling a ball on a string in a vertical plane, the minimum speed at the top of the motion is determined by setting the tension to zero, ensuring the string remains taut. To find this minimum speed, apply Newton's second law, recognizing the centripetal acceleration involved. For the maximum speed at the bottom of the swing, the maximum tension (Tmax) is used in the calculations. Again, Newton's second law is applied to solve for this maximum speed. Understanding these principles is crucial for analyzing the forces acting on the ball throughout its motion.
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a ball is whirled around with astring in the vertical plane. at the top of th ewhirl, what is the minimum speed which the ball can have before leaving the string? do you do sum of the forces and just set v = vmin? Then it says the maximum tension the string can have at the bottom is Tmax, what is vmax, the maximum speed of the ball without breaing the string, is it again sum of the forces? thanks
 
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So basically, you are given the tension at the bottom of the swing, and asked for the velocity there.

Yes, simply use F(net) = ma
to find v.
 
centripetal acceleration

PhysKid24 said:
a ball is whirled around with astring in the vertical plane. at the top of th ewhirl, what is the minimum speed which the ball can have before leaving the string?
I don't know what you mean by "leaving" the string. I suspect the question is "what's the minimum speed at the top of the motion that will keep the string taut". (Or do you mean "what's the minimum speed at the top of the motion that will break the string"?)
do you do sum of the forces and just set v = vmin?
You apply Newton's 2nd law, realizing that the ball is centripetally accelerated.
Then it says the maximum tension the string can have at the bottom is Tmax, what is vmax, the maximum speed of the ball without breaing the string, is it again sum of the forces?
Again, as Gokul43201 explains, apply Newton's 2nd law. But realize that the ball is centripetally accelerated.

Assuming I understand the problem: At the top of the motion, you want the minimum speed. Set the tension to zero and solve for the speed. At the bottom, you want the maximum speed; set the tension to Tmax and solve for the speed.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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