Why 2p=ln[(1-cost)/(1+cost)] => t=(1/coshp)^2

[astronomia84]

why
2p=ln[(1-cost)/(1+cost)] => t=(1/coshp)^2

?
?

 

[theperthvan]

why not?

 

[murshid_islam]

i think you wrote it wrong. it should be
$$\sin^{2}t = \left(\frac{1}{\cosh p}\right)^2$$

 

[cristo]

why
2p=ln[(1-cost)/(1+cost)] => t=(1/coshp)^2

?
?

What is the actual question you are asking here? Are you asking why, or if, the left implies the right. Have you done anything to attempt to show this? I doubt anyone will help unless you firstly specify your question, and secondly show some effort!