Why 2p=ln[(1-cost)/(1+cost)] => t=(1/coshp)^2

  • #1
astronomia84
20
0
why
2p=ln[(1-cost)/(1+cost)] => t=(1/coshp)^2

?
?
 
Last edited by a moderator:

Answers and Replies

  • #2
theperthvan
184
0
why not?
 
  • #3
murshid_islam
442
17
i think you wrote it wrong. it should be
[tex]\sin^{2}t = \left(\frac{1}{\cosh p}\right)^2[/tex]
 
  • #4
cristo
Staff Emeritus
Science Advisor
8,140
74
why
2p=ln[(1-cost)/(1+cost)] => t=(1/coshp)^2

?
?

What is the actual question you are asking here? Are you asking why, or if, the left implies the right. Have you done anything to attempt to show this? I doubt anyone will help unless you firstly specify your question, and secondly show some effort!
 

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