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Homework Statement:
 Two forces of 3 N and 4 N are acting at a point such that the angle between them is 60 degrees. Find the resultant force.
Relevant Equations:
 ##tan(q) = \frac{3. sin60^0}{4 + 3.cos 60^0}## = 0.472
Magnitude R of the resultant force is R =
##\sqrt {3^2+4^2+2∗3∗4∗cos60^0}##
= ##\sqrt {9+6+12}##
= ##\sqrt 37 = 6.08 N##
Direction of R is given by finding the angle q,
##tan(q) = \frac{3. sin60^0}{4 + 3.cos 60^0}## = 0.472
##q=tan^−1(0.472)q= tan^−1(0.472) = 25.3^0##
Thus R is 6.08N in magnitude and is at an angle of ##25.3^0## to the 4N force.
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