Why anhydrous ZnCl2 is used in Groove's Process?

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Anhydrous ZnCl2 is essential in Groove's Process for converting primary alcohols into alkyl halides via an SN2 reaction. The presence of ZnCl2 facilitates the formation of a better leaving group by coordinating with the hydroxyl group, thus enhancing the electrophilicity of the carbon atom. This coordination occurs before the transition state, ensuring that the C-O bond weakens effectively. Hydrated ZnCl2 would not provide the same level of reactivity due to the presence of water molecules, which would hinder the necessary interactions.

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avistein
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Why anhydrous ZnCl2 is required for 1 degree alcohols to convert into alkyl halides? It is a SN2 reaction; so the weakening of C-OH bond can be done with H+ of HCl. Oxygen from the OH group can donate its lone pair to H+ and O develops a positive charge which weakens the C-OH bond.Then bond between C and Cl will be forming and bond between C and O will be breaking in the transition state.Then what is the necessity of anhydrous ZnCl2?
 
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What role does ZnCl2 play? Would it be able to play that role once the cation is hydrated?
 

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