Why are core electrons removed from atoms on X-ray irradiation in XPS?

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Discussion Overview

The discussion revolves around the removal of core electrons from atoms during X-ray irradiation in X-ray Photoelectron Spectroscopy (XPS) and the comparative use of different X-ray sources, particularly Al Kα and Cu Kα, in this context. Participants explore the mechanisms behind electron ejection and the implications of photon energy on the process.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants suggest that core electrons are removed because they are highly localized to the parent atoms, unlike outer electrons which are part of overlapping orbitals in solids.
  • It is proposed that the cross-section for absorption varies for different electron levels and photon energies, influencing the signal strength for core versus outer electrons.
  • One participant notes that weakly bound electrons behave like free electrons, making scattering from X-rays impossible due to momentum conservation constraints.
  • There is a discussion about the use of Cu Kα photons in X-ray Diffraction (XRD) and whether they can eject electrons, with some participants questioning why higher energy photons do not yield observable photoemission in XRD.
  • Another participant points out that while Cu Kα can theoretically be used for XPS, its larger line width compared to Al Kα affects resolution, and typical XRD conditions may not allow for detection of emitted photoelectrons.

Areas of Agreement / Disagreement

Participants express differing views on the mechanisms of electron ejection and the effectiveness of various X-ray sources. There is no consensus on the specific reasons why Cu Kα photons do not lead to observable electron ejection in XRD, indicating ongoing uncertainty and debate.

Contextual Notes

The discussion highlights limitations related to the understanding of electron behavior under different photon energies and the conditions under which XPS and XRD are performed. Assumptions about electron binding energies and the nature of solid-state electron interactions are also noted but remain unresolved.

madhusoodan
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[Mentor's note: Post moved to its own thread]

Hi
Please let me know why core electrons are removed from the atoms on x-ray irradiation in XPS, though it was easier to outer electrons?
 
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Weakly bound electrons can be treated like free electrons, as the binding energy is much smaller than the X-ray energy.
For free electrons, scattering from x-rays is not possible as this would violate momentum conservation.
So scattering or excitation of electrons is only possible if they are appreciably bound to the nucleus.
 
madhusoodan said:
[Mentor's note: Post moved to its own thread]

Hi
Please let me know why core electrons are removed from the atoms on x-ray irradiation in XPS, though it was easier to outer electrons?

I think there is a misunderstanding here.

The core level electrons is used to distinguished the electrons that are highly localized to the parent atoms or ions of the solid, as opposed to the "band" electrons that are due to the overlapping of the outer orbitals in the formation of the solid. These band electrons usually show a dispersive feature that are not observed in the core-level electrons. So these are not simply "outer electrons" as in outer shell. There are no isolated "outer shell" electrons anymore in a solid.

XPS will excite all electron levels that are possible. However, the cross-section for absorption is different for different levels and different photon energies. There is also a difference in the density of states, or the density of levels. All of these will dictate the signal or peak strength for each level. You CAN see the Fermi edge at low binding energy. This means that you do get photoemission from the band electrons ( your outer electrons), but the signal is often weak when compared with the core level electrons, which usually dominate.

Zz.
 
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Thanks for clearing my earlier doubt.

Why can't Cu K alpha eject electrons from atoms of the sample in XRD?
As everyone knows, Al K alpha photon with 1486 eV energy is used for XPS to remove electrons from core levels. My doubt is why can't Cu K alpha photon with 8000+ eV do that?
 
madhusoodan said:
Thanks for clearing my earlier doubt.

Why can't Cu K alpha eject electrons from atoms of the sample in XRD?
As everyone knows, Al K alpha photon with 1486 eV energy is used for XPS to remove electrons from core levels. My doubt is why can't Cu K alpha photon with 8000+ eV do that?
Cu Kα can be used for XPS, as mentioned in this paper. However, even monochromated Cu Kα suffers from having a fairly large line width at ≈2.4 eV, in comparison monochromated Al Kα has a resolution <1 eV. XRD experiments using a lab source would usually be done in ambient conditions, so you wouldn't detect the emitted photoelectrons.
Typically for high energy x-rays, people go to a synchrotron light source (and in the future, probably an x-ray free electron laser source) instead.
 
Vagn said:
Cu Kα can be used for XPS, as mentioned in this paper. However, even monochromated Cu Kα suffers from having a fairly large line width at ≈2.4 eV, in comparison monochromated Al Kα has a resolution <1 eV. XRD experiments using a lab source would usually be done in ambient conditions, so you wouldn't detect the emitted photoelectrons.
Typically for high energy x-rays, people go to a synchrotron light source (and in the future, probably an x-ray free electron laser source) instead.

Thanks for the reply. Still I doubt whether electrons are ejected out from the atoms of sample or not during the xrd. Since energy of the Cu Kα photons is huge compared to Al kα photon,it seems electrons seems to be get ejected, however it is not observed and mentioned anywhere. Please help me to get clear picture of their differences.
 

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