Why are low pressure gas discharge lamps thermal sources?

In summary, the conversation discusses the emission of photons in Fock states in low pressure gas discharges. It is noted that generating single photon sources often requires complex schemes, and the question is raised as to why low pressure discharge lamps do not produce photons in Fock states. It is suggested that this may be due to collisions between a "thermal" stream of electrons and the gas, resulting in the photons inheriting the statistics of the electrons.
  • #1
Paul Colby
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When an atom makes a single photon transition it adds a single photon to the radiation field. One might then expect that a low pressure gas discharge would emit photons in Fock states? How is it that photon of an atomic spectral line produced in a low pressure gas discharge become thermalized?
 
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  • #2
This is not the clearest question statement so let me try to elaborate. To get single photon sources people resort to a number of relatively complex schemes. The most common seems to be using non-linear optical elements to do parametric down conversion. Basically one generates pairs of correlated photons and then uses one of the photons as a correlation gate on the second. Clearly people doing these kinds of experiments know their subject quite well and if there was a simpler means of generating photon Fock states they'd be using it. Hence the question, why does a low pressure discharge lamp not produce photons in Fock states.

After thinking about this some, I think the reason may have to do with the fact that low pressure lamps use collisions between a "thermal" stream of electrons and the gas. The generated photons aren't in Fock states because the photon inherit the statistics of the electrons. Does this sound like a reasonable guess?
 

1. Why are low pressure gas discharge lamps considered thermal sources?

Low pressure gas discharge lamps are considered thermal sources because they produce light through the heating and excitation of gas molecules. The gas inside the lamp is heated to high temperatures, causing it to emit light in the form of photons. This process is similar to how thermal sources such as incandescent light bulbs and fire emit light.

2. How does the gas inside a low pressure gas discharge lamp become heated?

The gas inside a low pressure gas discharge lamp is heated through the application of an electric current. This current is passed through the gas, causing collisions between the gas molecules and electrons. These collisions result in the transfer of energy to the gas molecules, increasing their temperature and causing them to emit light.

3. Are all types of low pressure gas discharge lamps thermal sources?

No, not all types of low pressure gas discharge lamps are thermal sources. Some types, such as fluorescent lamps, use a combination of gas discharge and phosphor coatings to produce light. In these lamps, the gas discharge is used to excite the phosphors, which then emit light. However, other low pressure gas discharge lamps, such as neon lights, rely solely on the heating and excitation of gas molecules to produce light.

4. What are the advantages of using low pressure gas discharge lamps as thermal sources?

One advantage of using low pressure gas discharge lamps as thermal sources is their high energy efficiency. They convert a large portion of the electrical energy into light, making them more efficient than incandescent bulbs. They also have a longer lifespan and produce less heat, making them safer to use. Additionally, they can produce a wide range of colors depending on the type of gas used.

5. Are there any limitations to using low pressure gas discharge lamps as thermal sources?

One limitation of using low pressure gas discharge lamps as thermal sources is that they require a high voltage to start the gas discharge. This can make them more expensive to operate and can also lead to flickering or a delay in the lamp turning on. Additionally, the gas inside the lamp can become depleted over time, causing a decrease in light output and eventually requiring replacement of the entire lamp.

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