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pp007
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Can anyone explain why C([0,1]) and C_{o} [tex]\oplus C [/tex][tex]\oplus C [/tex] (where C=complex ) are not isomorphic?
Office_Shredder said:The only definitions I've seen about functions vanishing at infinity require you to have points that go to infinity. How are you defining it on the interval (0,1)?
Office_Shredder said:From a first glance, it seems that vanishing at infinity on (0,1) just means continuous functions on [0,1] which are zero at 0 and 1. Just looking at intervals of the form (1/n, 1-1/n), for each epsilon f(x) can only be larger than epsilon on finitely many of these intervals, which means that looking at the limit at x goes to zero or 1 must be zero. Is that wrong?
The spaces C([0,1]) and C_{o} are not isomorphic because they have different algebraic structures. C([0,1]) is a Banach space, meaning it is a complete normed vector space, while C_{o} is not a Banach space. This difference in structure makes it impossible for the two spaces to be isomorphic.
The main difference between C([0,1]) and C_{o} is that C([0,1]) contains all continuous functions on the closed interval [0,1], while C_{o} only contains continuous functions that vanish at the endpoint 0. Additionally, as mentioned before, C([0,1]) is a Banach space while C_{o} is not.
No, C([0,1]) and C_{o} cannot be mapped onto each other. This is because isomorphisms preserve the algebraic structure of a space, and since C([0,1]) and C_{o} have different structures, it is impossible for them to be mapped onto each other.
Another notable difference between C([0,1]) and C_{o} is that C([0,1]) is a separable space, meaning it has a countable dense subset, while C_{o} is not separable. This means that C([0,1]) has "more" continuous functions than C_{o}, as it has a countable basis of functions while C_{o} does not.
While C([0,1]) and C_{o} may have some similar topological properties, such as being locally compact and Hausdorff, they cannot have all the same topological properties. This is because topological properties are preserved under isomorphisms, and since C([0,1]) and C_{o} are not isomorphic, they cannot have all the same topological properties.