Why Can't a Right Triangle Have Sides that Add Up to the Area of Squares?

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SUMMARY

The discussion centers on the application of the Pythagorean theorem to determine whether a triangle is a right triangle based on the areas of squares constructed on its sides. The areas provided are a² = 18, b² = 7, and c² = 27. The conclusion drawn is that 18 + 7 does not equal 27, confirming that the triangle is not a right triangle. The confusion arises from misapplying the theorem, as it specifically states that a² + b² = c², not a + b = c.

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So I've been working on Pythagorean stuff and it's pretty straight forward but then I got confused over something quite simple.

It's a geometry question so I'll try my best to illustrate the question.

So there's a triangle and we must evaluate whether it's a right angle. The lengths are not provided but each side of the triangle is also the side a square. So if we can find the length of a side from each square we can find out whether the triangle is a right triangle using the Pythagorean theorem.

The areas of the squares are provided.

The problem is the values say
a^2 = 18
b^2 = 7
c^2 = 27

Now the answer is 18 + 7 != 27 so it's not a right angle but I'm looking at this and thinking that if area is side^2 and it's a^2 = 18 then isn't the side a = sqr(18)?

So then I walk into a quagmire of sqr(18) + sqr(7) ?= sqr(27)... So what's wrong with me? I mean, the short answer.
 
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Ziggletooth said:
So I've been working on Pythagorean stuff and it's pretty straight forward but then I got confused over something quite simple.

It's a geometry question so I'll try my best to illustrate the question.

So there's a triangle and we must evaluate whether it's a right angle. The lengths are not provided but each side of the triangle is also the side a square. So if we can find the length of a side from each square we can find out whether the triangle is a right triangle using the Pythagorean theorem.

The areas of the squares are provided.

The problem is the values say
a^2 = 18
b^2 = 7
c^2 = 27

Now the answer is 18 + 7 != 27 so it's not a right angle but I'm looking at this and thinking that if area is side^2 and it's a^2 = 18 then isn't the side a = sqr(18)?

So then I walk into a quagmire of sqr(18) + sqr(7) ?= sqr(27)... So what's wrong with me? I mean, the short answer.

No quagmire at all.

The Pythagorean Theorem states $a^{2} + b^{2} = c^{2}$.
It says nothing of the $a + b = c$ sort. Thus, why does it concern you?
 
In fact, for a, b, c the lengths of the three sides of any triangle, you can't have "a+ b= c". You must have a+ b> c.
 

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