Garrulo
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Why in first order logic theories are not possible a demonstration with infinite steps?
The discussion revolves around the limitations of first order logic theories in demonstrating proofs with infinite steps. Participants explore the implications of finite syntactical proofs, the nature of non-standard natural numbers, and the challenges posed by non-standard models within first order logic.
Participants express differing views on the nature of proofs in first order logic, particularly regarding the use of infinite steps and non-standard models. The discussion remains unresolved, with multiple competing perspectives presented.
There are limitations in the clarity of some contributions, particularly regarding the terminology used to describe non-standard numbers and infinite steps. The discussion reflects a range of interpretations and assumptions about the foundational aspects of first order logic.
No infinite step, only finite steps but infinity pasesGarrulo said:Ok. But the problem I see is that demostration could have non standard steps, because for first order logic is impossible let she the non standard models out of a theory in first order language
Garrulo said:No infinite step, only finite steps but infinity pases
I recognize that English is not your native language, but frankly, what you have written is pretty much incomprehensible, especially "infinity pases" and "a number non standard natural numbers finite of steps". These make no sense.Garrulo said:infinite steps, sorry. But I refer to a demostration in a number non standard natural numbers finite of steps
I still don't get what you're asking. What do you mean by "non standard natural numbers steps"?Garrulo said:Other way: why not a formal demostration in a non standard natural numbers steps?