Why Can't I Solve for a2 Instead of a1 in Connected Objects Problem?

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Homework Help Overview

The discussion revolves around a problem involving connected objects and their accelerations, specifically focusing on the relationship between the accelerations a1 and a2. The original poster expresses confusion about why they cannot solve for a2 instead of a1, despite understanding the book's explanation that a2 = -a1.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to substitute -a2 for a1 in their calculations but finds that it does not yield the expected results. They question the consistency of signs in their equations and the implications of their assumptions about direction.

Discussion Status

Participants are exploring the implications of sign conventions and the consistency required in their equations. Some guidance has been offered regarding the need to maintain consistent signs, and the original poster has recognized a mistake in their approach to the problem.

Contextual Notes

There is an ongoing discussion about the directionality of acceleration and how it affects the equations being used. The original poster reflects on their previous misunderstandings regarding the polarity of the accelerations and the method of combining equations.

CVRIV
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I attached an image of the problem and solution from the book and my attempt at solving it. I don't need help solving the problem the way the book explains it; i understand that.

What I don't understand is why I can't solve for (a2) instead of (a1). The book says a2 = -a1, which makes sense to me, because the magnitudes are the same except the polarity for a2 is negative.

What about a1 = -a2? I tried solving the problem the same way except I substituted -a2 for a1 instead of the other way around and it doesn't work. I just don't understand why it wouldn't work.

Please help me understand this.
 

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You need to keep the signs consistent. In your first equation a positive a1 means the mass accelerates towards the edge. In your second equation a positive a2 means the mass accelerates downwards. That is possible - but then you have a1=a2 without the minus sign.
 
Why would positive a2 accelerate downwards? I thought positive a2 accelerates upwards?

In equation 2 I divided both sides by -1 so that I could cancel out the tension T. Was that not right?
 
Oh wow. I think I know what I did wrong. How stupid of me. :confused:
 
CVRIV said:
Why would positive a2 accelerate downwards? I thought positive a2 accelerates upwards?
It is arbitrary which direction you choose, but you have to be consistent.
 
Finally! The problem was that from the very start I was inverting the polarity of m1a2. I kept writing down T - m2g = -m2a2. I did that because I had it in my head that a2 was negative, which it is, but only after solving for a2. By assigning it as negative from the start, I was in fact just screw it all up. Also... I had it stuck in my head that I had to add the two equations together. I went back to the previous problem in the book, which as a Atwood's Machine problem, and it was subtracting the equations. I I thought I was doing it wrong so I told myself I have to subtract the problems. That's when I realized, fully realized, that it totally depended on the cancellation of T. I get it now. Thanks for your help.
 

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