Why can't SR explain why electrons do not crash into the nucleus?

In summary, the conversation discusses the speed and radius of an electron orbiting a hydrogen nucleus using classical mechanics and electromagnetism. The calculations show that the electron would need an infinite amount of energy to reach the speed of light and the minimum orbital radius permitted by relativity. However, it is argued that the electron would lose kinetic energy due to electromagnetic radiation, leading to a spiral motion and ultimately falling into the nucleus. The validity of this argument is questioned based on the assumption that an orbiting electron will radiate energy due to acceleration.
  • #36
Andrew, I know you want to set aside the radiation question, but that really is what is at issue here. It is the unequivocal testimony of physics textbooks everywhere that an orbiting charge radiates, and derivations of the energy flow rate abound at varying levels of rigor. You can't just brush it off like that.

But at the same time, I think you deserve an answer on this alleged controversy, which is why I am looking forward to reading those papers you cited. I'm sure I'll learn a great deal from them, so thank you for bringing them to my attention.
 
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  • #37
Andrew Mason said:
The question is whether it is the interaction of the fields of the charge and magnet that cause the radiation (and, because the charge has mass, also the charge's acceleration) or whether the interaction just causes the charge's acceleration and that acceleration, in turn, causes the radiation. Big difference.

But how do you tell the difference, in practice? How do you cause a charge to accelerate, without using electric or magnetic fields? Before you answer, "gravity", consider that in the context of general relativity, gravity isn't really a force at all, but "merely" a consequence of curved spacetime.
 
  • #38
jtbell said:
But how do you tell the difference, in practice? How do you cause a charge to accelerate, without using electric or magnetic fields? Before you answer, "gravity", consider that in the context of general relativity, gravity isn't really a force at all, but "merely" a consequence of curved spacetime.
That may be so, but acceleration is acceleration. And GR says that an accelerating mass (including a charged mass) and the same mass at rest in a gravitational field are equivalent. If, in fact, it is uniform acceleration that causes the charge to radiate, then it would have to radiate in a gravitational field.

I haven't read Feynman's Lectures on Gravitation (2002), although I am looking for a copy, but he starts one of those lectures, apparently, by saying:

'For example, in Feynman's "Lectures on Gravitation" he says "we have inherited a prejudice that an accelerating charge should radiate", and then he goes on to argue that the usual formula giving the power radiated by an accelerating charge as proportional to the square of the acceleration "has led us astray" because it applies only to cyclic or bounded motions.'​

See: http://www.mathpages.com/home/kmath528/kmath528.htm

AM
 
  • #39
Tom Mattson said:
Andrew, I know you want to set aside the radiation question, but that really is what is at issue here. It is the unequivocal testimony of physics textbooks everywhere that an orbiting charge radiates, and derivations of the energy flow rate abound at varying levels of rigor. You can't just brush it off like that.

But at the same time, I think you deserve an answer on this alleged controversy, which is why I am looking forward to reading those papers you cited. I'm sure I'll learn a great deal from them, so thank you for bringing them to my attention.
There has been quite a bit written on the subject. I have compiled this rather incomplete summary:

D. Boulware, "Radiation from a uniformly accelerated charge", Annals of Physics 124 , 169-187 (1980)

Kirk T. Mcdonald, "Hawking-Unruh Radiation and Radiation of a Uniformly Accelerated Charge", http://www.hep.princeton.edu/~mcdonald/accel/unruhrad.pdf (1998)

S. Parrott, "Radiation from a particle uniformly accelerated for all time", General Relativity and Gravitation 27 1463-1472, http://arxiv.org/PS_cache/gr-qc/pdf/9711/9711027.pdf (1995)

S. Parrott, "Radiation from Uniformly Accelerated Charge and the Equivalence Principle", Foundations of Physics, Volume 32, Number 3
March 2002, http://arxiv.org/abs/gr-qc/9303025

S. Parrott, "Relativistic Electrodynamics and Differential Geometry", New York: Springer Verlag, 1987.

A. Shariati, and M. Khorrami, "Equivalence Principle and Radiation by a Uniformly Accelerated Charge", Found. Phys. Lett. 12 427-439 (1999) http://arxiv.org/PS_cache/gr-qc/pdf/0006/0006037.pdf

Alfonso Rueda, Bernhard Haisch, "Contribution to inertial mass by reaction of the vacuum to accelerated motion" http://arxiv.org/abs/physics/9802030

A. K. Singal, "The Equivalence Principle and an Electric Charge in a Gravitational Field", General Relativity and Gravitation 27 953-967 (1995)

A. K. Singal, "The Equivalence Principle and an Electric Charge in a Gravitational Field II. A Uniformly Accelerated Charge Does Not Radiate", General Relativity and Gravitation 27 1371-1390 (1997)

"Abstract:The electromagnetic field of a charge supported in a uniform gravitational field is examined from the viewpoint of an observer falling freely in the gravitational field. It is argued that such a charge, which from the principle of equivalence is moving with a uniform acceleration with respect to the (inertial) observer, could not be undergoing radiation losses at a rate implied by Larmor's formula. It is explicitly shown that the total energy in electromagnetic fields, including both velocity and acceleration fields, of a uniformly accelerated charge, at any given instant of the inertial observer's time, is just equal to the self-energy of a non-accelerated charge moving with a velocity equal to the instantaneous “present” velocity of the accelerated charge. At any given instant of time, and as seen with respect to the “present” position of the uniformly accelerated charge, although during the acceleration phase there is a radially outward component of the Poynting vector, there is throughout a radially inward Poynting flux component during the deceleration phase, and a null Poynting vector at the instant of the turn around. From Poynting's theorem, defined for any region of space strictly in terms of fixed instants of time, it is shown that a uniformly accelerated charge does not emit electromagnetic radiation, in contrast to what is generally believed. Contrary to some earlier suggestions in the literature, there is no continuous passing of electromagnetic radiation from a uniformly accelerated charge into the region inaccessible to a co-accelerating observer."​

William E. Baylis, " Electromagnetic Radiation from an Accelerated
Charge[/url]" June 2003.

AM
 
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  • #40
Does an argument that electrons uniformly accelerated by gravity (which is unarguably a very different phenomenon than being uniformly accelerated by electromagnetic forces) do not emmit radiation meaningful in an atom where it could not possibly be bound by gravitational forces?

I'm having a hard time understanding the relevance of those papers. What have I missed?
 
  • #41
Locrian said:
Does an argument that electrons uniformly accelerated by gravity (which is unarguably a very different phenomenon than being uniformly accelerated by electromagnetic forces) do not emmit radiation meaningful in an atom where it could not possibly be bound by gravitational forces?

I'm having a hard time understanding the relevance of those papers. What have I missed?
You cannot make a distinction between gravitation and acceleration due to electromagnetic force without violating the principle of equivalence under GR. If GR is valid, then either a charge in the electromagnetic field does not radiate, or it does and we should be able to detect it. No one has been able to detect it.

AM
 
  • #42
Andrew Mason said:
You cannot make a distinction between gravitation and acceleration due to electromagnetic force without violating the principle of equivalence under GR. If GR is valid, then either a charge in the electromagnetic field does not radiate, or it does and we should be able to detect it. No one has been able to detect it.

AM

NO one has been able to detect that a charge in an EM field radiate? I don't understand. HOw many times do you need to be told that a charge in an EM field radiate?

It's like talking to a WALL!

Zz.
 
  • #43
ZapperZ said:
NO one has been able to detect that a charge in an EM field radiate? I don't understand. HOw many times do you need to be told that a charge in an EM field radiate?
Hang on Zz. I have never said that a (moving) charge in an EM field doesn't radiate. The question is whether the radiation is caused by acceleration.

If the charge radiates because of the interaction of the two em fields, the charge will necessarily accelerate. But that doesn't mean that it is the acceleration that causes the radiation. If it the charges' acceleration that generates the radiation, you have real problems with GR.

AM
 
  • #44
Andrew Mason said:
Hang on Zz. I have never said that a (moving) charge in an EM field doesn't radiate. The question is whether the radiation is caused by acceleration.

If the charge radiates because of the interaction of the two em fields, the charge will necessarily accelerate. But that doesn't mean that it is the acceleration that causes the radiation. If it the charges' acceleration that generates the radiation, you have real problems with GR.

AM

No I don't. You do.

Accelerating charges radiate. I have verified that EXPERIMENTALLY. This occurs no matter if it is accelerating linearly, or accelerating in a uniform circular motion. If you don't buy this, you have a real problem with experimental observations.

What is causing you to stand on top of your head is the issue that a charge that isn't moving in a gravitatonal field does not radiate.

If you are in the same reference frame as the charge, and the charge is accelerating, can you prove that you do see a radiation coming from the charge? And please, make sure you use the Lorentz covariant form of Maxwell Equations to do this.

Zz.
 
  • #45
Antiphon said:
Hans,

The confusion stems from the fact that a charge in uniform acceleration
does not radiate *in that accelerated frame*.

It does radiate when viewed from other frames in uniform motion, as your
equations correctly state.

From another post:

Antiphon.

It seems indeed true that, when using the Lienard Wiechert potentials, a
charge in uniform acceleration does not radiate *in that accelerated frame*.

One does get a non-zero vector potential because the relative velocity of
the retarded charge seen in the accelerated frame increases the longer
ago the EM potentials left the charge.

The vector potentials however stay constant in time in the case of, and
only in the case of, uniform acceleration. As a result there are no
fields which are associated with the acceleration.

These radiative fields re-appear again if observed from a reference frame
in uniform motion. At 90 degrees angles from the charge they have the
form of a E vector opposing the field that has caused the acceleration
of the charge.


Regards, Hans
 
  • #46
ZapperZ said:
What is causing you to stand on top of your head is the issue that a charge that isn't moving in a gravitatonal field does not radiate.

If you are in the same reference frame as the charge, and the charge is accelerating, can you prove that you do see a radiation coming from the charge? And please, make sure you use the Lorentz covariant form of Maxwell Equations to do this.
How am I to interpret this statement (cited above)?:
"From Poynting's theorem, defined for any region of space strictly in terms of fixed instants of time, it is shown that a uniformly accelerated charge does not emit electromagnetic radiation, in contrast to what is generally believed. Contrary to some earlier suggestions in the literature, there is no continuous passing of electromagnetic radiation from a uniformly accelerated charge into the region inaccessible to a co-accelerating observer."​

Is the author wrong?

AM
 
  • #47
Andrew Mason said:
How am I to interpret this statement (cited above)?:
"From Poynting's theorem, defined for any region of space strictly in terms of fixed instants of time, it is shown that a uniformly accelerated charge does not emit electromagnetic radiation, in contrast to what is generally believed. Contrary to some earlier suggestions in the literature, there is no continuous passing of electromagnetic radiation from a uniformly accelerated charge into the region inaccessible to a co-accelerating observer."​

Is the author wrong?

AM

... How did you managed to continually overlook the statement "... there is no continuous passing of electromagnetic radiation from a uniformly accelerated charge into the region inaccessible to a co-accelerating observer"?

How is this even anywhere close or applicable to "charge orbiting in a central potential"? Are YOU and the charge "co-accelerating" so much so that you are in this "inaccessible region" that would get no radiation?

This is VERY confusing because (i) you keep ignoring (or maybe you didn't understand) the stuff you're citing and (ii) you're applying different things to different situations that are not equivalent. For some odd reason, even after all this time and after all those replies, you still somehow do not see this.

Zz.
 
  • #48
ZapperZ said:
... How did you managed to continually overlook the statement "... there is no continuous passing of electromagnetic radiation from a uniformly accelerated charge into the region inaccessible to a co-accelerating observer"?
I am not sure what makes you think I overlooked it. My understanding is that this is a reference to the 'co-moving observer exception'. To explain why no radiation is detected from a charge in a gravitational field, the 'co-moving observer exception' has been developed. According to this theory, the lack of radiation from a stationary charge in a gravitational field is that it is there but not detected - that it is not accessible to a co-moving observer (ie. another observer who is at rest in the same gravitational field). What this paper seems to say - at least according to the abstract which I have quoted fully - is that there is no radiation period. There is no radiation detected by the co-moving observer and there is no "passing of electromagnetic radiation from a uniformly accelerated charge into the region inaccessible to a co-accelerating observer"

How is this even anywhere close or applicable to "charge orbiting in a central potential"? Are YOU and the charge "co-accelerating" so much so that you are in this "inaccessible region" that would get no radiation?

This is VERY confusing because (i) you keep ignoring (or maybe you didn't understand) the stuff you're citing and (ii) you're applying different things to different situations that are not equivalent. For some odd reason, even after all this time and after all those replies, you still somehow do not see this.
Well, it has been about 30 years since my last quantum physics and electromagnetism courses. But I think I am capable of understanding from the literature that the issue is still not satisfactorily resolved for some. In any event, the ad hominem approach to discussion and argument doesn't work any better in physics than in law.

AM
 
  • #49
Andrew Mason said:
I am not sure what makes you think I overlooked it. My understanding is that this is a reference to the 'co-moving observer exception'. To explain why no radiation is detected from a charge in a gravitational field, the 'co-moving observer exception' has been developed. According to this theory, the lack of radiation from a stationary charge in a gravitational field is that it is there but not detected - that it is not accessible to a co-moving observer (ie. another observer who is at rest in the same gravitational field). What this paper seems to say - at least according to the abstract which I have quoted fully - is that there is no radiation period. There is no radiation detected by the co-moving observer and there is no "passing of electromagnetic radiation from a uniformly accelerated charge into the region inaccessible to a co-accelerating observer"

Well, it has been about 30 years since my last quantum physics and electromagnetism courses. But I think I am capable of understanding from the literature that the issue is still not satisfactorily resolved for some. In any event, the ad hominem approach to discussion and argument doesn't work any better in physics than in law.

AM

1. You are doubting the EM model, in which an electron in a "circular orbit around a nucleus" would radiate EM radiation.

2. You used THIS paper that you are citing as an "example" that an accelerating charge need not radiate.

3. I asked you why would you think this two would make a fair comparison? One is where the observe is in the SAME accelerating frame, while the other, the observer is in a different frame where the electron is observed to be in a circular motion. The observe isn't IN the same frame as the accelerating electron.

If you cannot argue why those two situations are equivalent to each other, then this whole thread that you started is MOOT. They are different! They are SUPPOSED to be different from each other. This isn't unusual. If I'm moving at the same constant velocity as a bunch of moving charges, I see no current! I also detect no magnetic field! Are you then going to argue that classical E&M is wrong? Or some other principles are faulty?

The fact that you have been told EARLY on a few times that these are different (I see at least a couple of postings indicating accelerating reference frame of the observer and the charge) makes me wonder if you either did not understand what was meant by that, or you simply refuse to put any validity on such arguments.

Unless you can show me an example of a charge particle moving in a circular motion that does NOT radiate, this thread is finished.

Zz.
 
  • #50
In classical E&M, as written in hundreds of books, the radiation field-- the 1/r part-- is proportional to A, the acceleration of the charge (modulo some vector expressions) And, wonder of wonders, all these books agree. There is nothing in the derivation to suggest that uniform A is to be excluded.

So what's the problem? This standard, well verified derivation does not include gravitation in the General Relativistic fashion -- it could not, originally, as GR had not been developed when the derivations of radiation were first done. When GR is included, Maxwell's equations in general covarient form automatically involve the metric structure of space, and that's a different ball game, and a difficult one at that. We live in a flat space, to a good approximation, so the usual form of the radiation formulas are valid.

Regards,
Reilly Atkinson
 
  • #51
ZapperZ said:
Unless you can show me an example of a charge particle moving in a circular motion that does NOT radiate, this thread is finished.
First of all, this thread was supposed to be about special relativity. My question related to the reason the electron does not collide with the proton and whether there was something other than QM (the uncertainty principle), that could possibly explain it.

Let's forget about orbits and just look at an electron colliding with a proton. If you confine the electron to a space the size of a several proton diameters - [itex]10^{-14} m[/itex], then according to the uncertainty principle,

[tex]\Delta p\Delta x > \hbar /2[/tex]
So [tex]\Delta p > 5\times 10^{-35}/10^{-14} = 5\times 10^{-21}[/tex] kg. m/sec

Since m = 9.1 x 10-31 kg., this means that the uncertainty in speed is:

[tex]\Delta v > 5.5\times 10^{9}m/sec^2[/tex] which is 18 x the speed of light.

To achieve that level of uncertainty of position, there would have to be a non-zero probability that the electron is traveling at a speed greater than c, which would seem to violate SR and, in any event, would require infinite energy.

One cannot confine the electron to a space that small. And it is not the uncertainty principle that is the limiting factor. It is special relativity and, ultimately, energy.


As far as your request for an example is concerned, what about a charge in gravitational orbit? If it is the centripetal acceleration that causes the charge to radiate, then a charge in gravitational orbit should radiate. But if it does radiate, then gravitational orbit is not equivalent to uniform motion (ie. I can tell the difference locally between an electron in gravitational orbit and an electron at rest in an inertial frame of reference).

AM
 
  • #52
[itex]\vec{p} \neq m \vec{v}[/itex]

As far as your request for an example is concerned, what about a charge in gravitational orbit?

It's traveling in a straight line. (More precisely, geodesic)
 
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  • #53
Andrew Mason said:
Let's forget about orbits and just look at an electron colliding with a proton. If you confine the electron to a space the size of a several proton diameters - [itex]10^{-14} m[/itex], then according to the uncertainty principle,

[tex]\Delta p\Delta x > \hbar /2[/tex]
So [tex]\Delta p > 5\times 10^{-35}/10^{-14} = 5\times 10^{-21}[/tex] kg. m/sec

Since m = 9.1 x 10-31 kg., this means that the uncertainty in speed is:

[tex]\Delta v > 5.5\times 10^{9}m/sec^2[/tex] which is 18 x the speed of light.

To achieve that level of uncertainty of position, there would have to be a non-zero probability that the electron is traveling at a speed greater than c, which would seem to violate SR and, in any event, would require infinite energy.

One cannot confine the electron to a space that small. And it is not the uncertainty principle that is the limiting factor. It is special relativity and, ultimately, energy.

It looks like you "forgot" MORE than just orbits. You forgot that when you get to that speed, you can no longer use the rest mass! Or maybe you also intend to forget special relativity...;

As far as your request for an example is concerned, what about a charge in gravitational orbit? If it is the centripetal acceleration that causes the charge to radiate, then a charge in gravitational orbit should radiate. But if it does radiate, then gravitational orbit is not equivalent to uniform motion (ie. I can tell the difference locally between an electron in gravitational orbit and an electron at rest in an inertial frame of reference).

AM

Let me get this right. You are STILL insisting that (i) a charge in a gravitational orbit is IDENTICAL to (ii) a charge that is stationary in a gravitational field??!

You not only have problems with E&M, you also have problems with classical mechanics! And I'm not even going to ask you where you have seen a charge particle moving in a gravitational orbit that does NOT emit radiation.

Zz.
 
  • #54
Andrew Mason said:
As far as your request for an example is concerned, what about a charge in gravitational orbit? If it is the centripetal acceleration that causes the charge to radiate, then a charge in gravitational orbit should radiate. But if it does radiate, then gravitational orbit is not equivalent to uniform motion (ie. I can tell the difference locally between an electron in gravitational orbit and an electron at rest in an inertial frame of reference).

AM

I haven't really had time to sort through the arguments in this thread, but if you read some of the papers you linked to, some physicists have indeed proposed that charged particles do violate the weak Equivalence Principle. So there is some degree of controversy when dealing with charged particles and gravity. (Also - there's the problem that no one has experimentally been able to answer the question whether an unsupported electron accelerated by gravity radiates). But you'll notice that none of the papers you cited ever mention that this means that there is a potential problem in electrodynamics itself. Because there is none.

Also in another post, you also seem to be separating out "acceleration" and "electromagnetic interaction/force". Something about the electromagnetic interaction causing the radiation, but not the acceleration per se, if I understand you correctly. I don't think you can do this, from a theoretical standpoint. Or at least, it seems somewhat meaningless to do so.

You're by no means obligated to believe the modern theories and interpretative frameworks of classical and quantum physics, but unless you have better alternatives which explain experimental phenomenon just as well if not better, few others will be in your camp.
 
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  • #55
ZapperZ said:
It looks like you "forgot" MORE than just orbits. You forgot that when you get to that speed, you can no longer use the rest mass! Or maybe you also intend to forget special relativity...;
Quite right, as Hurkyl quickly pointed out. The point is that a huge amount of energy is required to confine the electron to such a small space, and that energy is simply not available.


Let me get this right. You are STILL insisting that (i) a charge in a gravitational orbit is IDENTICAL to (ii) a charge that is stationary in a gravitational field??!
When did I say that? I said it is equivalent to a charge at rest in an inertial frame. A charge at rest in a gravitational field is equivalent to an accelerating charge.

And I'm not even going to ask you where you have seen a charge particle moving in a gravitational orbit that does NOT emit radiation.
Then you are saying that a charge in circular orbit is not equivalent to a charge at rest in an inertial frame?

AM
 
  • #56
Mr. Mason -- If you could confine an electron in a sphere of just several proton radii, you certainly will get a free trip to Stockholm. You are perfectly free to invent your own brand of physics. You seem to avoid any study of the issues with which you are concerned, and you do not listen(read). With all due respect, I get the strong sense that you are mainly concerned with pushing your own agenda, and, unfortunately, too many of us have ended up playing your game. Bye.

Reilly Atkinson
 
  • #57
juvenal said:
Also in another post, you also seem to be separating out "acceleration" and "electromagnetic interaction/force". Something about the electromagnetic interaction causing the radiation, but not the acceleration per se, if I understand you correctly. I don't think you can do this, from a theoretical standpoint. Or at least, it seems somewhat meaningless to do so.
Is it? If it is acceleration that causes radiation, then acceleration in a gravitational field should cause the same radiation (which would necessarily mean that the radiation arises due to the interaction of the electron's field with itself). This seems to create a serious GR problem. If it is not the acceleration there is no GR problem.

You're by no means obligated to believe the modern theories and interpretative frameworks of classical and quantum physics, but unless you have better alternatives which explain experimental phenomenon just as well if not better, few others will be in your camp.
I don't have a camp. I don't have a theory. I am not challenging QM. I am just asking a question.

AM
 
  • #58
reilly said:
Mr. Mason -- If you could confine an electron in a sphere of just several proton radii, you certainly will get a free trip to Stockholm.
Well isn't that the point? You can't confine the proton to such a small space. Special relativity says that it requires too much energy. If you can't confine it to such a space, it can't crash into the nucleus.

You are perfectly free to invent your own brand of physics. You seem to avoid any study of the issues with which you are concerned, and you do not listen(read). With all due respect, I get the strong sense that you are mainly concerned with pushing your own agenda, and, unfortunately, too many of us have ended up playing your game. Bye.
I am sorry that you seem to take a personal affront to the discussion. I am just trying to gain some insight into an interesting area by asking a question. I can assure you that I am not smart enough and will never be knowledgeable enough to have an agenda to push when it comes to quantum mechanics.

AM
 
  • #59
To all:

Is it really all that important to have an answer to this right this second? Why don't all the interested parties just take their time with the papers that have been cited, and see if the results really are applicable to the problem. Then we can get to the bottom of this without being so frustrated, and we can learn something in the process.
 
  • #60
Andrew Mason said:
Is it? If it is acceleration that causes radiation, then acceleration in a gravitational field should cause the same radiation (which would necessarily mean that the radiation arises due to the interaction of the electron's field with itself). This seems to create a serious GR problem. If it is not the acceleration there is no GR problem.
AM

You seem to have neglected the first part of my response when I said that the GR part is controversial. And you keep using the controversial GR part as a way to discount electrodynamics, no? That's why this argument has become circular - your only valid point seems to be that there is a controversy about charged particles radiating in GR. Do you agree?

The problem I see is that we're venturing off into the philosophy of science at this point.

Physicists come up with models, and these models are always effective models of reality. Even if string theory turns out to be right, it will be an effective model up to the highest energies that are experimentally testable. And with each of these models there involves some interpretation of what the models actually mean. And the question of to what extent such a model represents "reality".

In the classical theory of electrodynamics (as detailed by Jackson's textbook), acceleration and radiation go hand-in-hand when we're talking about an observer at rest watching an accelerated electron. This model works for almost all cases where electromagnetic interactions are involved, and in the cases where it breaks down, we rely on quantum mechanics and/or quantum electrodynamics. To separate acceleration and EM interaction in these models is meaningless.

You make the point that maybe in some other model, one can separate out acceleration and EM interaction, and that this is necessary due to the possible problem in GR you mention above. The answer that the majority of us, I believe, have, is first, that it isn't necessary since some general relativist may be able to resolve things. And second, we honestly don't care given that classical EM and QM work just fine otherwise, and are the best models we have given the energy scales and laboratory conditions that are typical. There is no doubt, for example, that QM explains atomic and molecular physics. Maybe, like Einstein, you don't believe in QM, but most of us are perfectly happy with it, in the sense that we are happy with its predictions of experimental phenomenon.
 
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  • #61
Mr. Mattson -- Mr. Mason, apparently without recognition, has had his question answered in this thread numerous times. Further, the issue of the equivalence principle has absolutely nothing to do with the stability of the hydrogen atom, or any other atom for that matter. It should be dealt with in another thread , which I believe has been the case.

The fact that Mr. Mason could state that relativity has not been applied to the issue of atomic stability for hydrogen suggests to me that he does not know enough to recognize a valid answer to his concerns. Particularly as an ex-professor, I say he does not need answers here, rather he should take the enormous amount of info provided, retire to his study, and study so that he can at least recognize correct answers, or better yet, formulate his own answers. Indeed, as I've said in this thread, he's asked an interesting question. Now let him supply an interesting answer. This is what I would say if I were still partipating in this thread, which I am not.

Regards,
Reilly Atkinson
 
  • #62
Andrew Mason said:
I assumed that this non-QM explanation was wrong and that I was missing something obvious somewhere. I have tried to figure out why this is not at least a plausible explanation. I can't.
I seem to recall that Dirac looked at all this when he developed relativistic quantum mechanics. I am afraid you are barking up an old tree that Dirac has already peed on. Worth a look anyway.
 
  • #63
reilly said:
Mr. Mattson -- Mr. Mason, apparently without recognition, has had his question answered in this thread numerous times. Further, the issue of the equivalence principle has absolutely nothing to do with the stability of the hydrogen atom, or any other atom for that matter. It should be dealt with in another thread , which I believe has been the case.

The fact that Mr. Mason could state that relativity has not been applied to the issue of atomic stability for hydrogen suggests to me that he does not know enough to recognize a valid answer to his concerns. Particularly as an ex-professor, I say he does not need answers here, rather he should take the enormous amount of info provided, retire to his study, and study so that he can at least recognize correct answers, or better yet, formulate his own answers. Indeed, as I've said in this thread, he's asked an interesting question. Now let him supply an interesting answer. This is what I would say if I were still partipating in this thread, which I am not.

Regards,
Reilly Atkinson

I'm beginning to concur with Reilly. If one cannot see the distinct difference between an acceleration of an object in a circular motion, with an object AT REST in a gravitational field, even after repeated explanation, then there's nothing else that can be said. The continued bastardization of the equivalence principle here is astounding.

As I've said earlier, if I am not shown where a charged particle in a circular motion doesn't radiate, then this thread is finished... and it is.

Zz.
 
  • #64
Either people are not fully reading/understanding my posts or I am not fully understanding theirs. I keep telling Zz, for example, that I am NOT saying that an electron in gravitational orbit is equivalent to an electron at rest in a gravitational field. Rather that it is equivalent to an electron at rest in an inertial frame of reference. So I don't understand the last post. We don't seem to be joining issue on the problem here, for some reason.

In any event, we seem to be making little progress. So I will graciously take all of your collective advice and retire to my study to reflect on all these weighty matters. Many thanks for putting up with me. :smile:

AM
 
  • #65
I only would like to make a consideration.

We know that charged particles radiates when they accelerates, and I'm totally sure of it.

But when we talk about charged particles in this context, do we mean that they have to be spatially localized?

Since it's not possible to localize an electron in a precise point of its 1s orbit in an atom, maybe it's not possible to say that it accelerates. In a particle accelerator, or even in an high energy atom orbit, it's another story.

The fact the 1s electron could be "spread" around the nucleus, makes me wonder if the electron could be continuously reassorbing the very EM energy it radiates.
 
  • #66
Are you aware of how OLD of a thread you were replying to? I think the last 2 threads you replied to were all "old" threads that were no longer active.

Zz.
 
  • #67
I know how old they are. If this is a problem, you suggest me to begin a new thread?
 
  • #68
No, it's not a problem. Sometime people who reply to these old threads don't seem the realize that the "train has left the station", so to speak.

Zz.
 
  • #69
Thanks.
Have you ever heard about some kind of model of electron in an atom emitting and reabsorbing its own energy?
 
  • #70
lightarrow said:
Thanks.
Have you ever heard about some kind of model of electron in an atom emitting and reabsorbing its own energy?

There are "stochastic electrodynamics" models around in which everything is bathing in some background noise radiation, which compensates exactly (stochastically) the loss due to radiation by acceleration, maintaining some kind of dynamical equilibrium which corresponds in many respects to the quantum-mechanical solution:

* Journal of Scientific Computing Volume 20 , Issue 1 (February 2004)
Pages: 43 - 68

* A stochastic electrodynamics interpretation of spontaneous transitions in the hydrogen atom; H M França et al 1997 Eur. J. Phys. 18 343-349

* Daniel C. Cole & Yi Zou, Quantum Mechanical Ground State of Hydrogen Obtained from Classical Electrodynamics, Physics Letters A, Vol. 317, No. 1-2, pp. 14-20, (2003)

*Daniel C. Cole & Yi Zou, Analysis of Orbital Decay Time for the Classical Hydrogen Atom Interacting with Circularly Polarized Electromagnetic Radiation, Physical Review E, 69, 016601, (2004)

You take these results for what you like them to be. I don't know if these are just fancy coincidences or mean anything more.
 

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