In post #2, the calculated force between the two conductors is
Fa = +∂/∂a [1/(2μ0)∫v B2 dV] (with a plus sign)
This is very unusual, and unexpected, because the repulsive force is in the direction of increasing the stored magnetic energy.
In a mechanical system, like a compressed spring, W = ½ k x2, so the force is
Fx = −∂W/∂x = −kx (with a minus sign).
So the force is in a direction to reduce the stored mechanical energy.
Smythe, in Static and Dynamic Electricity, third edition, sections 7.18 and 8.02, discusses the sign difference at some length. In the magnetic case, the external circuit provides energy to maintain a constant current in the conductors as the conductor is moved. Smythe states "The [magnetic case] is exactly the opposite of the electric case, where the force on equal and opposite charges tends to bring them together and destroy the electric field."
Bob S