- #1
fog37
- 1,568
- 108
Hello Forum,
A black body is an object with emissivity=1 that absorbs as well as it emits. Does that mean that its temperature T stops rising after it reaches thermal equilibrium but it rises before then since absorption dominates over emission?
What about a white body? That would be a perfect reflector. All the incident energy will be rejected and emitted (reflect). That sounds very similar, from a net energy standpoint, to what happens with a blackbody...
so what is the difference? Does the white body reach this steady state (incident energy in= energy out) instantaneously? Theoretically, the white body temperature should be zero and never rise...
Thanks
fog37
A black body is an object with emissivity=1 that absorbs as well as it emits. Does that mean that its temperature T stops rising after it reaches thermal equilibrium but it rises before then since absorption dominates over emission?
What about a white body? That would be a perfect reflector. All the incident energy will be rejected and emitted (reflect). That sounds very similar, from a net energy standpoint, to what happens with a blackbody...
so what is the difference? Does the white body reach this steady state (incident energy in= energy out) instantaneously? Theoretically, the white body temperature should be zero and never rise...
Thanks
fog37