Why Do Complex Ions with the Same Number of Ligands Form Different Shapes?

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SUMMARY

Complex ions with the same number of ligands can adopt different geometries due to the electronic configuration of the transition metals involved. For instance, [Cu(Cl)4]2+ typically forms a tetrahedral shape, while [NiCl2(NH3)2] adopts a square planar configuration. This distinction arises primarily from the d8 electron configuration of certain transition metals, which allows for hybridization of orbitals into sp2d configurations, minimizing electron-electron repulsion. Understanding these geometric preferences is crucial for mastering transition metal chemistry.

PREREQUISITES
  • Understanding of coordination chemistry
  • Familiarity with transition metal electron configurations
  • Knowledge of valence bond theory
  • Basic concepts of hybridization in chemistry
NEXT STEPS
  • Study the principles of coordination chemistry and ligand types
  • Explore the concept of d-orbital hybridization in transition metals
  • Learn about the geometrical preferences of different transition metal complexes
  • Investigate the role of electron-electron repulsion in molecular geometry
USEFUL FOR

Chemistry students, particularly those preparing for exams in inorganic chemistry, educators teaching coordination chemistry, and researchers interested in transition metal complexes.

joeyjo100
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I'm currently trying to cram knowledge of the transition metals into my head for a chemistry final exam, although i have come across a stumbling block when reading about the 3 dimensional shapes that complex ions form.

My textbooks say that complex ion with 4 coordination bonds will form a tetrahedral shape, such as [Cu(Cl)4]2+.

But then it says that some complex ions with coordination numbers of four can form square planar shapes, such as [NiCl2(NH3)2].

What causes these two complex ions with the same number of ligands to have different shapes? Has it got something to do with the shape or charge of the ligands?
 
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joeyjo100 said:
I'm currently trying to cram knowledge of the transition metals into my head for a chemistry final exam, although i have come across a stumbling block when reading about the 3 dimensional shapes that complex ions form.

My textbooks say that complex ion with 4 coordination bonds will form a tetrahedral shape, such as [Cu(Cl)4]2+.

But then it says that some complex ions with coordination numbers of four can form square planar shapes, such as [NiCl2(NH3)2].

What causes these two complex ions with the same number of ligands to have different shapes? Has it got something to do with the shape or charge of the ligands?

Most transition metal complexes with a coordination number of 4 favor tetrahedral geometries. The exception is for ions with a d8 configuration of their valence electrons. This is because the complex can lower its energy in this geometry (obviously). IIRC, you can explain this in terms of valence bond theory, by hybridizing the empty s, px, py, and dx2-y2 orbitals to make 4 empty sp2d hybrid orbitals in a square planar configuration to accept the ligand electron pairs. The occupied d-orbitals are then the dz2, dxy,dxz, and dyz orbitals. If you are good at visualizing orbitals, you will see that the lobes of those orbitals holding the 8 valence electrons of the metal ion are more or less optimally oriented to point between the lobes of the empty sp2d hybrids that are acting as lone pair acceptors, which minimizes the overall electron-electron repulsion energy in the complex.
 
I came.across a headline and read some of the article, so I was curious. Scientists discover that gold is a 'reactive metal' by accidentally creating a new material in the lab https://www.earth.com/news/discovery-that-gold-is-reactive-metal-by-creating-gold-hydride-in-lab-experiment/ From SLAC - A SLAC team unexpectedly formed gold hydride in an experiment that could pave the way for studying materials under extreme conditions like those found inside certain planets and stars undergoing...

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