Why do objects thrown from a cliff hit the ground at the same speed?

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Homework Help Overview

The discussion revolves around a physics problem involving two balls thrown from a cliff, one upwards and the other downwards, both with the same initial speed. Participants explore the question of which ball hits the ground with greater speed, while considering the effects of gravity and neglecting air resistance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of energy as a potential explanation for the speeds of the balls upon impact. There is an exploration of the concept of velocity versus speed, particularly in relation to the direction of motion for the ball thrown upwards.

Discussion Status

The discussion is progressing with participants clarifying concepts and addressing misconceptions about velocity and speed. Some guidance has been offered regarding the relationship between the balls' speeds at impact, but no consensus has been reached on the final interpretation of the problem.

Contextual Notes

It is noted that the analysis assumes air resistance is negligible, which may affect the conclusions drawn about the speeds of the balls.

samona
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Homework Statement


two balls are thrown from a cliff. one is thrown directly up, the other directly down, each with the same initial speed, and both hit the ground below the cliff. which ball hits the ground at the greater speed?

The Attempt at a Solution


I know the answer is that they both his the ground at the same speed. But why?
 
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samona said:

Homework Statement


two balls are thrown from a cliff. one is thrown directly up, the other directly down, each with the same initial speed, and both hit the ground below the cliff. which ball hits the ground at the greater speed?

The Attempt at a Solution


I know the answer is that they both his the ground at the same speed. But why?

This is only true when drag from the air is neglected, btw.

Consider conservation of energy. For each ball, PE + KE is a constant. Think about what happens to the ball thrown upward. What is its speed at the instant when it comes back downward to pass the point it was thrown from?
 
When it returns to the position it started out as, then the velocity should equal the initial velocity.
 
samona said:
When it returns to the position it started out as, then the velocity should equal the initial velocity.

Careful there. When it was thrown upward, its direction was upward. When it comes back down, its direction is reversed. Since velocity is a vector with both magnitude and direction, you can't say the final velocity equals the initial velocity. You can, however, say that the final speed equals the initial speed.

So the ball comes back down with the same speed it was thrown up at. Now its velocity (both magnitude and direction) is the same as the second ball that was thrown downward from the start. Can you immediately see the rest of the way to the solution?
 
Got it! Thank you!
 
You're welcome. :smile:
 

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