Why Do Rockets Measure Different Collision Times in Relativity?

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Homework Help Overview

The discussion revolves around a relativistic physics problem involving two rockets moving towards each other at significant fractions of the speed of light. The original poster seeks to understand why the time until collision differs according to each rocket's frame of reference, given their initial distance and speeds as observed from Earth.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the time until collision based on relative velocity and distance, questioning the differing results perceived by each rocket.
  • Some participants clarify the importance of frame of reference, noting that distances measured in the Earth frame differ from those in the rockets' frames.
  • Others suggest using Lorentz transformations to analyze the situation from the perspective of each rocket.
  • There is a focus on understanding how simultaneity and length contraction affect the measurements of distance and time in different frames.

Discussion Status

The discussion is ongoing, with participants providing guidance on using Lorentz transformations and emphasizing the need to consider both space and time coordinates. There is a productive exchange of ideas, but no consensus has been reached on the final approach to solving the problem.

Contextual Notes

Participants note that the problem is constrained by the relativistic effects of speed and distance, and there is an acknowledgment of the complexity involved in transforming measurements between different reference frames.

snellslaw
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Hello physics forums people, could you please help me?

Homework Statement



According to an Earth observer, rocket 1 has speed 0.800c, rocket 2 has speed 0.600 c and rockets are initially 2.52x10^12 m apart. The rockets are approaching each other.
According to each Rocket, how long is it before they collide?

Answer:
Rocket 1: 60 min
Rocket 2: 80 min

Homework Equations



From velocity addition equations, I found that the velocity of each rocket according to the other rocket is 0.946.

The Attempt at a Solution



Now I don't understand why the rockets think that the collision occurs in different times. Isn't it 2.52x10^23 / 0.946c = 8879 s for each? (I know this is wrong since it doesn't match the answer but not why.)
I believe that each rocket thinks the other is 2.52x10^12 m away... is this wrong? (I think it is but I don't know why)
 
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You have to be more careful. The distance ##2.52\times 10^{12}\text{ m}## is measured in the Earth rest frame. The speed you calculated is measured in the rockets' rest frame.

You also have to remember that events simultaneous in the Earth frame aren't necessarily simultaneous in the rockets' frames.
 
Last edited:
Thanks! How would I calculate the distance in the rocket's rest frame (for each rocket)?
 
By the way, I know how to solve this problem by first calculating the time of collision as seen from the Earth. I just want to know how to calculate it using distances and speeds from the point of view of the rockets as well.
 
Try calculating the space-time coordinates of the other ship as observed in the rest frame of the first ship.
 
By length contraction, ship A thinks B is a distance 2.52x10^12/√(1-0.8^2) away
thus the time is 2.52x10^12/√(1-0.8^2) / (0.946c) = 14799... still not right :(
 
No, you need to calculate both the space and time coordinates of the other ship. It's not simple length contraction.
 
Thanks but I don't know how to proceed. Could you please help me out?
 
Use the Lorentz transformations.
 
  • #10
Let S denote the rest frame of Earth and S', the rest frame of rocket 1.

In the Earth's frame, the rockets are initially ##2.52\times 10^{12}\text{ m}## apart. So we'll set up the coordinate systems to rocket 1 is passing through x=0 when t=0. We'll call this space-time point event A. Rocket 2 is therefore at ##x=2.52\times 10^{12}\text{ m}## when t=0. This is event B.

In rocket 1's frame, we'll set up the coordinates so that event A is at x'=0 and t'=0. When we set up the coordinate systems this way (so that the origins of the two coordinate systems coincide), the coordinates are related by the Lorentz transformations:
\begin{align*}
x' &= \gamma(x-\beta ct) \\
ct' &= \gamma(ct - \beta x)
\end{align*} where ##\beta = v/c## is the velocity of S' relative to S and ##\gamma = 1/\sqrt{1-\beta^2}##. Using these equations, you can calculate the space-time coordinates of event B in S'. Once you have them, you can calculate when the two rockets will collide, as seen by an observer on rocket 1.
 

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