Why Do Voltage-Current Graphs in the Franck-Hertz Experiment Show Tops and Dips?

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Homework Help Overview

The discussion revolves around the Franck-Hertz experiment, specifically focusing on the voltage-current graph and the reasons for observed tops and dips, as well as the low electron count at the collector. Participants are exploring the underlying physics of electron collisions and energy levels in mercury atoms.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to explain the behavior of the voltage-current graph, particularly the relationship between anode voltage and current dips related to inelastic collisions. Questions are raised about the implications of reverse bias voltage on electron collection and the overall current levels.

Discussion Status

Some participants have suggested alternative sources for clarification, indicating that the original explanations may lack clarity. There is ongoing inquiry into the reasons for the low electron count at the collector, with no consensus reached on a definitive explanation.

Contextual Notes

Participants are considering the effects of potential differences and thermal equilibrium on electron behavior, with an emphasis on the experimental setup and its implications for current measurement.

Kristoffer Linder
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Homework Statement


I have two questions concerning the Franck-Hertz experiment on Mercury. The first one is to explain the tops and dips in the voltage-current graph (https://en.wikipedia.org/wiki/File:Franck-Hertz_en.svg). The second question consider the experimental setup, and why there is so few electrons in the collector.

Homework Equations

The Attempt at a Solution


My attempted answer to the first question, that was not recognized by my teacher, was that:

"as one increases the anode voltage, there is a sharp dip in the counter current at the energy at which such can occur. At higher voltages the counter current starts to rise again but eventually the electrons gain sufficient energy to once again inelastically collide with the Mercury atoms and thus excite them to a higher energy level. The observed current-voltage curve should be steadily rising with a superimposed series of dips; the separation of two dips will correspond to the difference in energy of the ground state and first excited state in the mercury atoms."

And the answer to the second question, which also was not recognized, was that:

"There is a potential difference between the grid anode and the collector (denoted as P in the figure) as well. This potential difference is called the reverse bias voltage. As the electrons makes it through the cloud of Mercury atoms they will be subject to a stopping force slowing down their speed and thus the energy. This reverse bias voltage may be seen as a filter that filters the electrons that does not have a sufficient energy to reach the collector. Finally the electrons that reach the collector will induce a current in the circuit following the collector"

Do anyone know another way of answering those two questions?
 
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About question 2, your answer explains what the reverse bias voltage does (it acts as a kind of filter, yes, to filter those electrons only that have high enough energy) but it doesn't seem to answer, at least explicitly, why there are few electrons at the collector, why the current measured is at the levels of milliampere.
 
darth boozer said:
I would suggest reading other sources as the Wikipedia explanation is not very clear.
http://hyperphysics.phy-astr.gsu.edu/hbase/FrHz.html is a good place to start.

I think this answer the first question, but the question with why there are so few electrons at the collector still remains.
 
Kristoffer Linder said:
why there are so few electrons at the collector
Thermal equilibrium
 

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