Why Do We Use Integer Atomic Masses in Nuclear Reactions?

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The atomic masses of isotopes listed in Clark's tables are experimentally obtained and presented in decimal form, reflecting their abundance in nature. In nuclear reactions, these masses are often rounded to integers for convenience and clarity, particularly in professional contexts where specific isotopes are relevant. The concept of mass excess, as defined in Schaums book on Modern Physics, relates to the difference between the atomic mass and the integer mass used in reactions, which is linked to the energy changes during nuclear processes. This rounding is significant because it simplifies calculations while still aligning with the principles of mass-energy equivalence established by Einstein. Understanding these relationships is crucial for comprehending energy release and absorption in nuclear fission and fusion.
Amith2006
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Homework Statement


In Clark's tables, the atomic masses of various isotopes are given which are decimal form. Are these experimentally obtained masses? Moreover, while writing nuclear reactions we do not use these, instead they are represented as integers. Is it just for convenience or is there any particular reason for this?In Schaums book on Modern Physics, they have defined the difference between the 2 masses as mass excess.Could somebody please explain the relation between these 2 values?

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Amith2006 said:

Homework Statement


In Clark's tables, the atomic masses of various isotopes are given which are decimal form. Are these experimentally obtained masses? Moreover, while writing nuclear reactions we do not use these, instead they are represented as integers. Is it just for convenience or is there any particular reason for this?In Schaums book on Modern Physics, they have defined the difference between the 2 masses as mass excess.Could somebody please explain the relation between these 2 values?

My chem teacher in high school said it was about their abundance in the universe (if there's more 16g Oxygen than 15g Oxygen, the decimal will be closer to 16, to put it simply) I don't know if it's abundance on the Earth, or abundance of the Universe. I'd assume they use spectroscopy for measuring the Universe's abundance and have no idea how they'd measure Earth's abundance beyond our little sliver of inhabitation on it's surface.

I think the nuclear reactions round to the nearest integer, or sometimes use the types of isotopes used in your profession (like physics for the health sciences might deal with molybdenum-xx into technetium-99, since radiologists use this to help make detections in living systems).

The excess mass has something to do with the energy that is released (and absorbed for fusion? not sure...) in the fission reactions.

Remember how Einstein equated mass to energy? In Nuclear physics, you get to actually see how that works...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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