Why does diode breakdown into conduction when reverse biased?

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Diode breakdown into conduction during reverse bias occurs when the electric field in the depletion zone intensifies beyond a critical level, allowing current to flow through mechanisms like Zener or avalanche breakdown. These breakdown processes are generally non-destructive and reversible, provided the current does not cause thermal damage to the semiconductor. The analogy of a steep hill illustrates that while a small voltage can push current in the forward direction, a significantly higher reverse voltage is required to overcome the energy barrier. This results in a chain reaction where accelerated electrons collide with lattice sites, releasing more electrons and creating a large current. Understanding these principles is crucial for applications involving diodes in electronic circuits.
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why does diode breakdown into conduction when reverse biased?
 
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i didn't get, so could you please elaborate my above statement ?
 
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Elaborate on what? You must be more precise in your question.

http://en.wikipedia.org/wiki/P–n_junction#Reverse_bias
The strength of the depletion zone electric field increases as the reverse-bias voltage increases. Once the electric field intensity increases beyond a critical level, the p–n junction depletion zone breaks down and current begins to flow, usually by either the Zener or the avalanche breakdown processes. Both of these breakdown processes are non-destructive and are reversible, as long as the amount of current flowing does not reach levels that cause the semiconductor material to overheat and cause thermal damage.

These links explains the two reverse breakdown modes.
http://en.wikipedia.org/wiki/Zener_breakdown
http://en.wikipedia.org/wiki/Avalanche_breakdown
 
While the above is correction, a handwavy, more pop-science version would be:

If you put enough reverse bias on a diode than you can accelerate electrons hard enough that when they hit a lattice site they can release more electrons and so on, making a chain reaction that causes a large current to flow.
 
I'll try an explanation. Think of the PN junction as a hill with a steep angle, not 90 say 80 degrees or so. When a bowling ball is sent down the hill, no problem it just rolls down the hill and proceeds on. But try to send one up the hill and you need a very high velocity to achieve this. The PN junction is an energy hill in one direction the voltage "pressure" that pushes it down the hill only takes a little energy to travel that distance. However in the opposite direction much more energy is needed, and the two mechanisms, as pointed out in Baluncore's response are Zener or avalanche breakdown process. Both present a tipping point (particular voltage or pressure) of the necessary energy to achieve useful amounts of current in the reverse direction. Then analogdesign's response elaborates further on the events that occur in the atomic lattice.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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