Why Does dV/V Equal ln(Vd/Va) in Physics Homework?

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SUMMARY

The equation dV/V = ln(Vd/Va) is a fundamental relationship in physics that describes the change in volume relative to the initial volume. This equation is derived from the principles of calculus and logarithmic functions, specifically in the context of thermodynamics and fluid dynamics. Understanding this relationship is crucial for solving problems related to volume changes in various physical systems. The discussion highlights the need for clarity in applying this equation to specific homework problems.

PREREQUISITES
  • Basic understanding of calculus, specifically differentiation and integration.
  • Familiarity with logarithmic functions and their properties.
  • Knowledge of thermodynamics principles, particularly volume changes in gases.
  • Experience with physics problem-solving techniques.
NEXT STEPS
  • Study the derivation of the equation dV/V = ln(Vd/Va) in thermodynamic contexts.
  • Explore applications of logarithmic functions in physics problems.
  • Learn about the implications of volume changes in ideal gases using the Ideal Gas Law.
  • Review calculus techniques for solving differential equations related to physical systems.
USEFUL FOR

Students studying physics, particularly those tackling thermodynamics and fluid dynamics, as well as educators looking to clarify concepts related to volume changes in physical systems.

Donna14
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Homework Statement



See attachment

In the first place I don't understand why you can just say: dV/V = ln(Vd/Va) ( was given in lecture slides)

And I am not sure if my attempt to the solutions is any good...
Hope Someren can help me a bit with b and c


Homework Equations





The Attempt at a Solution



See second attachment
 

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I think you have forgotten to attach the files.
 
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BOAS said:
I think you have forgotten to attach the files.

Can you help me now the attachment is there? Thanks!
 

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