Why Can Volume Be Used Instead of Specific Volume in PV Diagrams?

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Homework Help Overview

The discussion revolves around the application of volume versus specific volume in the context of calculating work done in a thermodynamic cycle, specifically in relation to the ideal gas law and isothermal processes.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the equations for work done in a thermodynamic cycle and question the omission of mass in the formula presented. There is also a discussion about the notation used for volume and specific volume.

Discussion Status

Several participants express confusion regarding the formula for work, specifically the absence of mass in the equation. There is acknowledgment of differing interpretations of the formula, and some suggest it may be a typographical error in the reference material. The discussion is ongoing with multiple viewpoints being considered.

Contextual Notes

Participants note that the reference material for the fundamentals of engineering exam presents a similar formula without mass, leading to speculation about potential errors in the presentation being discussed.

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1. Problem Statement

The problem asks to find the net work from one complete cycle A-B-C. Problem 13, starting on page 66 of the slide show here:

https://engineering.purdue.edu/~xe/Files/FE%20Review/Thermo/FEThermoReview2013.pdf

Homework Equations


ideal gas law: PV=mRT
Boyle's Law: W=RTln(v2/v1)

3. Attempt at solution

I understand most of the solution, but on page 67, says that W=R*T*ln(Vb/Va) is equivalent to W=p*Va*ln(Vb/Va), assuming ideal gas and constant mass. I don't understand why you can use volume here instead of specific volume.

From the ideal gas law: PV=mRT and RT=PV/m. So I thought it should be W=p*Va/m*ln(Vb/Va). Why can we eliminate m here?

Thank you!
 
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There should be an m in the equation W=R*T*ln(Vb/Va). It should read W=m*R*T*ln(Vb/Va).
 
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What's wrong is "W = RT ln(Vb/Va)". It should be W = mRT ln(Vb/Va).
Notice that the wrong formula is never used in the computations.

P.S. why do they put a slash thru the V's?
 
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One equation for isothermal work is W = m*R*T* ln(Vb/Vb). He has either made a mistake by omitting the number of moles or he has calculated the heat for 1 mole.
 
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Thanks for the responses. Good to know I'm not crazy.

Chestermiller said:
There should be an m in the equation W=R*T*ln(Vb/Va). It should read W=m*R*T*ln(Vb/Va).

In the reference material for the fundamentals of engineering exam, the formula also does not include mass. I guess its a typo. Maybe that's where the author of the presentation got the formula from.

rude man said:
P.S. why do they put a slash thru the V's?

I think it is to differentiate between volume and specific volume. It confused me at first though.
 

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