Why Does dy Change in Solving Linear Differential Equations?

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robertjford80
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Homework Statement



Handwritten-style derivation of an integrating factor method for a linear first-order ODE: v(x) dy/dx + P(x)v(x)y = v(x)Q(x); then d/dx(v(x)·y) = v(x)Q(x); then v(x)·y = integral of v(x)Q(x) dx, with side notes about multiplying by v(x) and integrating with respect to x.




I don't understand why in step 2 dy turns into d and why +P(x) dissappears
I also don't see a difference between v(x)y and v(x)*y

In step three why does the d disappear. I see that dx is going over to the right side, well, what about the numerator d?
 
d/dx is the differential operator. dy/dx just means d/dx operating on y. You should probably read a bit more elementary calculus to get used to this notation.

You start from a differential equation
[tex]\frac{dy}{dx} + P(x) y = Q(x)[/tex]
and then you multiply both sides of this equation with a function [itex]v(x)[/itex] (which you have to find first) which has the property that the left hand sides of steps 1 and 2 are equal.

In step 3, you integrate both sides of the equation with respect to x.