Why Does External Resistance Equal Internal Resistance for Maximum Power?

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SUMMARY

The maximum power transfer theorem states that maximum power is delivered to an external resistance when it equals the internal resistance of the source. In this discussion, the relationship is derived using the formula P = I^2 * R, where I is the current calculated as I = E/(R + r). By differentiating the power equation with respect to external resistance R and setting the derivative dP/dR to zero, the condition for maximum power delivery is established. This principle is crucial for optimizing circuit performance in electrical engineering.

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Homework Statement


My textbook says that the power delivered by the battery to external resistance network will be maximum when the external resistance equals the internal resistance? Why is it so?
p = I^2 * R, so greater the external resistance, greater the power(even if it exceeds internal resistance)

Homework Equations


P = VI ;)


The Attempt at a Solution


Clueless about this one.
 
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In the circuit the current is written as
I = E/(R + r) where E is the emf of the battery and r is the internal resistance of the battery.
So P = I^2*R =[ E^2/(R + r)^2]*R
The power delivered by the battery depends on the external resistance. So find
dP/dR and equate it to zero to get the condition for maximum power delivery
 
Thanks a lot. :cool:
 

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