Why Does Including the Zero Vector Make a Set Linearly Dependent?

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Including the zero vector in a set of vectors makes it linearly dependent because it can be expressed as a linear combination of other vectors with non-zero coefficients. The zero vector can be represented by setting the coefficients of the other vectors to zero, satisfying the definition of linear dependence. Additionally, if a collection of vectors is linearly dependent, any larger set that includes those vectors must also be linearly dependent. This is because the dependence relationship can be extended by adding zero coefficients for the new vectors. Thus, the presence of the zero vector or any linearly dependent vectors prevents the set from forming a basis.
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Homework Statement


Prove that any collection of vectors which includes \theta (zero vector or null vector)is linearly dependent. Thus, null vector cannot be contained in a basis.


The Attempt at a Solution


Well, I know that in order for a collection of vectors to to be linearly dependent, one vector can be expressed as a linear combination of other vectors such as:
let s be some non-zero scalar
let v be vectors

s1v1 + s2v2 + ... + skvk = 0

but let's say that v2 was a zero vector (is this what the question is asking?),
-s2v2 = s1v1 + s3v3 + ... + skvk?
I don't quite get the phrase "any collection of vectors which includes 0(theta)"
 
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Start off by proving the set containing ONLY the zero vector is linearly dependent. It's easiest to use the direct definition here: A set of vectors v1,..., vn is linearly dependent if and only if there exist coefficients s1,..., sn such that not all the si are zero (but some of them are allowed to be) and that

s1v1 + ... + snvn = 0

If you only have the zero vector, what s1 can you pick to satisfy this? Then consider if you add additional vectors... what coefficients can you pick for them?
 
Okay thanks, I got that one. How about this one?

1. Homework Statement
Prove that if the vectors b1, b2,...bm are linearly dependent, then any collection of vectors which contains the b's must also be linearly dependent

3. The Attempt at a Solution
So to be linearly dependent,
s1b1 + s2b2 +... + smbm = 0
given that the scalar s is not equal to zero.

How should I go about proving this one?
 
dracolnyte said:
Okay thanks, I got that one. How about this one?

1. Homework Statement
Prove that if the vectors b1, b2,...bm are linearly dependent, then any collection of vectors which contains the b's must also be linearly dependent

3. The Attempt at a Solution
So to be linearly dependent,
s1b1 + s2b2 +... + smbm = 0
given that the scalar s is not equal to zero.
There is NO "scalar s" in what you wrote! You mean that "at least one of the s1, s2, ..., sm is not 0."

How should I go about proving this one?
If a collection of vectors includes the b's, take the coefficients of the addtional vector to all be 0.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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