Why Does Multiplying Pressure by \(10^5\) Help in Calculating Depth?

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Homework Help Overview

The discussion revolves around understanding the relationship between pressure and depth in a fluid, specifically using the equation P = ρgh. Participants are exploring why multiplying pressure by \(10^5\) is necessary for their calculations.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants attempt to solve for depth using the pressure equation but express confusion regarding the need to convert pressure units. Questions arise about unit consistency and the implications of using different unit systems.

Discussion Status

Some participants have provided insights about unit conversions and the importance of using consistent units in calculations. There is an ongoing exploration of the relationship between pressure in atmospheres and Pascals, but no consensus has been reached on the necessity of the multiplication factor.

Contextual Notes

Participants note potential issues with unit mixing, specifically between atmospheres and SI units, which may affect their calculations. The original poster's reference to a specific pressure value suggests a need for clarity on unit conversions.

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Homework Statement


a1qqh1.png

PART B

Homework Equations


[tex]P = \rho gh[/tex]


The Attempt at a Solution


Well I tried doing 412 = (1025)(9.8)h.. Divide by 10045 (9.8 x 1025). And ended up getting .041..
I found out that I need to use 412 x 105 for the pressure which I have no idea why.

Any help?

Also, the answer is 4100m
 
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iRaid said:

Homework Statement


a1qqh1.png

PART B

Homework Equations


[tex]P = \rho gh[/tex]


The Attempt at a Solution


Well I tried doing 412 = (1025)(9.8)h.. Divide by 10045 (9.8 x 1025). And ended up getting .041..
I found out that I need to use 412 x 105 for the pressure which I have no idea why.

Any help?

Also, the answer is 4100m

You are mixing your units. "Atmospheres" is not an mks unit. You should write units in your equations as you go, to make sure that they are consistent (LSH units = RHS units, and the units of any quantities you are adding are the same).
 
In your equation P=ρgh, P is measured in Pascals (Pa)
 
Oh right thanks
 

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