Why does only the amino group react in the synthesis of paracetamol?

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The synthesis of paracetamol involves the reaction of 4-aminophenol with acyl chloride or acid anhydride, where only the amino group (R-NH2) reacts, not the hydroxyl group (R-OH). The amino group is more nucleophilic, effectively attacking the acyl group and displacing chloride. The phenolic hydroxyl does not participate significantly due to the low concentration of the phenolate anion, which is a better nucleophile than free phenol. Additionally, the phenolate ester formed under basic conditions is a strong electrophile, but it is primarily amidated by the amino group, resulting in minimal ester formation.

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I was reading through my textbook and apparently when 4-aminophenol reacts with an acyl chlordie / acid anhydride (as in the synthesis of paracetamol) only the R-NH2 group reacts and NOT the R-OH group.

Why is this?
 
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The amino group is considered more nucleophilic to attacking the acyl group and displacing chloride, than a phenolic hydroxyl. The phenolate anion will not be present in enough quantity to interefere (it is somewhat better nucleophile than free phenol hydroxyl).

Of the phenolate ester that is formed under strongly basic conditions, it is also a good electrophilic species like the acyl chloride, and is amidated by the amino group attack on the ester carbonyl releasing the phenolate anion. One wouldn't expect to see much if any ester as a result.
 

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