Why does particle size affect EM radiation scattering

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Particle size significantly affects electromagnetic radiation scattering due to diffraction effects, which occur when the size of the particle is comparable to the wavelength of the light. When light interacts with non-fundamental particles, it diffracts at specific angles and intensities that depend on the particle's size. This relationship is crucial for applications like particle size measurement. The impact parameter and interaction cross-section also play important roles in understanding these scattering phenomena. Overall, the size of the particle relative to the wavelength determines the scattering behavior of electromagnetic radiation.
Justin Hawk
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It is my understanding that electromagnetic radiation is absorbed by an electron and then emitted at another angle. So why does particle size affect scattering when the phenomenon involves electrons? Also, why does the size of the wavelength of the light relative to the diameter of the particle matter?
 
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For fundamental particles it doesn't.
What matters is the impact parameter and the cross-section for the interaction.

Are you thinking of things like dust? eg. Rayleigh scattering?

In that case it is a diffraction effect - you need the barrier to be of the same order as the wavelength to get noticeable interference.
 
For non-fundamental particles, when light (electromagnetic beam) hits the particle, the beam diffracts at a certain angle and intensity, dependent on particle size. This is the basis of particle size measurements, and you can find more information about it on the following link


http://www.quantachrome.co.uk/en/laser-diffraction.asp
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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