Curious3141
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middleCmusic said:I think your method is fair, as it doesn't use the numerical expression for pi - rather it just uses relationships between [the ratio of a circle's circumference and diameter] and right triangles. (The former of which happens to be pi).
If OP wants a numerical expression for pi - one that generates it - perhaps an infinite series is what OP wants (although I feel from the responses that OP may be missing some of the prerequisite material, but perhaps it's just a language barrier).
How about something like this:
[itex]\pi = 4(1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \frac{1}{9})[/itex]
I don't know the derivation though unfortunately.
Perhaps you meant this: [itex]\pi = 4(1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \frac{1}{9} - ...)[/itex]
That ellipsis ('...') is all important.
Alternatively, you could've stated: [itex]\pi \approx 4(1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \frac{1}{9})[/itex], but the approximation is really quite mediocre with so few terms.