Why does plastic container slides off at the same speed?

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Homework Help Overview

The discussion revolves around the behavior of two cylindrical plastic containers on a turntable, one empty and one filled with lead shot, as the turntable's speed increases. Participants are exploring the conditions under which the containers slide off the turntable, particularly focusing on the role of mass and friction in circular motion.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between centripetal force and frictional force, questioning how these forces interact as the turntable speed increases. There is an exploration of equations related to circular motion and the conditions for sliding off the turntable.

Discussion Status

Some participants have provided insights into the equations governing the motion of the containers, noting that mass does not appear to affect the outcome in this scenario. However, there remains uncertainty about the implications of these findings and whether the reasoning is fully understood.

Contextual Notes

Participants are working under the assumption that the coefficient of static friction is constant and that both containers are initially at the same distance from the center of the turntable. There is a lack of consensus on the interpretation of the equations and their implications for the sliding behavior of the containers.

gijungkim
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Homework Statement


Two small cylindrical plastic containers with flat bottoms are placed on a turntable that has a smooth flat surface. Canister A is empty; canister B contains lead shot. Each canister is the same distance r from the center. The coefficient of static friction between the canisters and the turntable is Us . When the speed of the turntable is gradually increased,

a. only the lighter container slides outward off the turntable; the heavier one stays on.

b. only the heavier container slides outward off the turntable; the lighter one stays on.

c. both containers slide off the turntable at the same turntable speed.

d. the lighter container slides inward.

e. the heavier container slides inward.

Homework Equations

The Attempt at a Solution



The answer is c, but I don't understand why. Can anyone explain it with equations??
 
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gijungkim said:

Homework Statement


Two small cylindrical plastic containers with flat bottoms are placed on a turntable that has a smooth flat surface. Canister A is empty; canister B contains lead shot. Each canister is the same distance r from the center. The coefficient of static friction between the canisters and the turntable is Us . When the speed of the turntable is gradually increased,

a. only the lighter container slides outward off the turntable; the heavier one stays on.

b. only the heavier container slides outward off the turntable; the lighter one stays on.

c. both containers slide off the turntable at the same turntable speed.

d. the lighter container slides inward.

e. the heavier container slides inward.

Homework Equations

The Attempt at a Solution



The answer is c, but I don't understand why. Can anyone explain it with equations??
Initially, the two containers follow the turntable, correct?

That means that they are undergoing circular motion, which is an acceleration, correct?

The only way that this can happen is if there is a centripetal force pushing in.

What is the force for the two canisters? F= ma. a = v^2/r

The cans fall off when the frictional force becomes less than the centripetal force.

Write two equations for the two cans, and see how the two velocities compare to each other.
 
Quantum Defect said:
Initially, the two containers follow the turntable, correct?

That means that they are undergoing circular motion, which is an acceleration, correct?

The only way that this can happen is if there is a centripetal force pushing in.

What is the force for the two canisters? F= ma. a = v^2/r

The cans fall off when the frictional force becomes less than the centripetal force.

Write two equations for the two cans, and see how the two velocities compare to each other.
so Us*Fn < mv^2 / r this is when the container slides off right? And if I simplify this equation, I get Us * g = v^2 / r. Since there is no m in this equation, mass doesn't matter right? I don't know if I did it right or not haha
 
gijungkim said:
so Us*Fn < mv^2 / r this is when the container slides off right? And if I simplify this equation, I get Us * g = v^2 / r. Since there is no m in this equation, mass doesn't matter right? I don't know if I did it right or not haha

Sure it's right. The mass doesn't matter. The 'centripetal force' is proportional to mass and so is the normal force.
 
Dick said:
Sure it's right. The mass doesn't matter. The 'centripetal force' is proportional to mass and so is the normal force.
Thank you! :)
 

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