Why Does Poisson's Ratio Differ for Different Materials?

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SUMMARY

Poisson's ratio varies across materials due to differences in their intermolecular forces and compressibility. While the theoretical value of Poisson's ratio is 0.5 for incompressible materials, real-world materials exhibit a range of values, typically between 0 and 0.5. The relationship between Poisson's ratio (ν), bulk modulus (K), and shear modulus (G) is defined by the equation ν = (3K - 2G) / (2(3K + G)). Understanding these principles is crucial for material science and engineering applications.

PREREQUISITES
  • Understanding of Poisson's ratio and its significance in material science.
  • Familiarity with bulk modulus (K) and shear modulus (G).
  • Basic knowledge of Young's modulus and its relationship to material properties.
  • Concept of incompressibility in materials.
NEXT STEPS
  • Research the implications of Poisson's ratio in different materials, focusing on elastic and plastic deformation.
  • Explore the derivation and applications of the equation ν = (3K - 2G) / (2(3K + G)).
  • Study the effects of intermolecular forces on the mechanical properties of materials.
  • Investigate the behavior of liquids in relation to shear modulus and Poisson's ratio.
USEFUL FOR

Material scientists, mechanical engineers, and students studying material properties and mechanics will benefit from this discussion.

Prathamesh
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For any rod Poisson's ratio should be
same i.e. 0.5 (we get this ans if we find
(dr/r) / (dl/l) ) assuming that
volume of rod always remains constant...
But why it is not so ?
We have different ratios for different materials..
 
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Prathamesh said:
For any rod Poisson's ratio should be
same i.e. 0.5 (we get this ans if we find
(dr/r) / (dl/l) ) assuming that
volume of rod always remains constant...
But why it is not so ?
We have different ratios for different materials..

the materials try to keep their volume constant but intermolecular forces are 'realistic' forces and many a time it falls short and the ratio goes to 0.3 or such values. the hooks law which is used also can be said to be working approximations.
 
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For their volume to be constant, all materials would have to be incompressible.
 
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Chestermiller said:
For their volume to be constant, all materials would have to be incompressible.

Not quite; they would only need to have a shear modulus of zero. A liquid would satisfy this requirement, even if it is not perfectly incompressible. You can conclude this from the identity $$\nu=\frac{3K-2G}{2(3K+G)}$$ where ##\nu## is the Poisson's ratio, ##K## is the bulk modulus, and ##G## is the shear modulus. Note that the Poisson's ratio is undefined for a perfectly incompressible material (i.e., one for which ##K=\infty##).
 
Mapes said:
Not quite; they would only need to have a shear modulus of zero. A liquid would satisfy this requirement, even if it is not perfectly incompressible. You can conclude this from the identity $$\nu=\frac{3K-2G}{2(3K+G)}$$ where ##\nu## is the Poisson's ratio, ##K## is the bulk modulus, and ##G## is the shear modulus. Note that the Poisson's ratio is undefined for a perfectly incompressible material (i.e., one for which ##K=\infty##).
If the shear modulus is zero, then Young's modulus is zero, which means that, unless the Poisson ratio is equal to 1/2, the bulk modulus is zero. If the Young's modulus is not zero and the Poisson ratio is equal to 1/2, the bulk modulus is infinite, and the material is incompressible.
 

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