Why does polynomial long division work?

Click For Summary
SUMMARY

Polynomial long division is a method used to divide polynomials, similar to numerical long division. In the discussion, the example of dividing (x² - x - 6) by (x - 1) illustrates that factoring is not beneficial since (x - 1) is not a factor of the numerator. Instead, the division can be expressed as (x(x - 1) - 6)/(x - 1), resulting in a quotient of x with a remainder of -6. Synthetic division is also mentioned as an alternative method for performing polynomial division.

PREREQUISITES
  • Understanding of polynomial expressions and operations
  • Familiarity with basic algebraic concepts
  • Knowledge of synthetic division techniques
  • Ability to manipulate fractions and remainders
NEXT STEPS
  • Study the process of polynomial long division in detail
  • Learn about synthetic division and its applications
  • Practice factoring polynomials to identify divisors
  • Explore the relationship between polynomial division and the Remainder Theorem
USEFUL FOR

Students in algebra courses, educators teaching polynomial division, and anyone seeking to understand the fundamentals of polynomial operations.

BenB
Messages
5
Reaction score
0
So I'm in a college algebra class and I know how to do polynomial long division. I'm curious as to why polynomial long division works. I've looked at some proofs, but they use scary symbols that I don't understand (I am quite dumb). Do I need very high-level math to comprehend why polynomial long division works? What I'd like to see, if it's possible, is an example of a polynomial division problem being solved with just basic algebra. How would I solve, for example, (x2-x-6)/(x-1) without long division? (sorry, don't know how to use Latex)
 
Mathematics news on Phys.org
How would I solve, for example, (x2-x-6)/(x-1) without long division? (sorry, don't know how to use Latex)

Have you tried factoring the numerator?
 
Last edited by a moderator:
Since neither factor is x- 1, I don't believe factoring helps with the division.

Instead write this as
\frac{x^2- x}{x- 1}+ \frac{-6}{x- 1}= \frac{x(x- 1)}{x- 1}+ \frac{-6}{x- 1}
= x+ \frac{-6}{x- 1}
so x- 1 divides into x^2- 1 x times with remainder -6.

You could also use "synthetic division" as shown here: http://www.purplemath.com/modules/synthdiv.htm
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K