Why does resonance in Kundts tube differ from theoretical calculations?

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Homework Help Overview

The discussion revolves around an experiment conducted using a Kundt's tube, where the original poster measured resonance frequencies and wavelengths of sound waves in a 75 cm tube filled with sand. They observed discrepancies between their measurements and theoretical calculations of resonance lengths.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster shares their experimental results and calculations, prompting questions about the methods used to determine resonance lengths. Participants inquire about the setup and the nature of resonance in closed pipe resonators.

Discussion Status

Participants are actively engaging in clarifying concepts related to resonance and the behavior of sound waves in the tube. Some guidance has been offered regarding the nature of standing waves and resonance conditions, but multiple interpretations and questions remain open.

Contextual Notes

The original poster mentions that the tube length is fixed at 0.75 meters and expresses uncertainty about the accuracy of their measurements and calculations. There is also a lack of information regarding the temperature, which may affect the speed of sound calculations.

Alec
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I made an experiment in a tube, 75 centimeters.
There was sand in it so I could distinguish one wave length.
the biggest one I got was 0.335 meters at a frequency of 480Hz and the smallest was 0.07 meters at a frequency of 2000 Hz.
I calculated the resonance in the tube as 1.5 meters as the biggest and 0.3 meters as the smallest.
I'm now wondering why this differs so much from my measuring in the tube?
 
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how did you calculate the 1.5m and the .3m?
 
I used the formula L = lambda / 2 for the normal tone.
L = lambda for 1st over tone and L = 3 * lambda / 2 for 2nd over tone and finaly L = 5 * Lambda / 2 for 3rd? over tone (I got help in another thread).
L being the length of the tube 0.75 meters.
 
Could you explain your lab. It sounds as if this pipe was a closed pipe resonator, but i need you to explain the lab meaning what you did in order to change the lengths of the pipe with the sand.
 
The tube was half open, it had a tonegenerator plugged into it, and then there was sand. Once you turned the frequency up the sand began to vibrate because of the sound waves that was sent out. You were able to distinguish two nodes and measure the distance between them. Once you turned up the frequency the nodes got closer to each other (only on certain frequencies), we never got it really high 2000 Hz was the highest.
Do you see the scenario now?
 
do you know what it means to resonate?
 
No, sorry I don't.
 
another question and i will try to help, did you change the lengths of the tube at all?
 
No, never, it's determined to 0.75 meters. (made of glass and impossible to change). Thank you!
 
  • #10
well, i don't have to much time right now, and it is taking you a while to reply, so ill explain what resonance is in my own words and ill explain it to you in a way for you to understand. Whenever a sound wave goes through a tube it will reflect of the end, in both an open pipe and closed pipe resonators. If the high pressure wave reflects back and reaches the source(what creates the waves) at the same time that another wave is leaving then those two waves, the reflected and the one leaving will reinforce each other and you will be able to hear a louder sound at that point it is said that the air column is in resonace with the source.
 
  • #11
when the reflected wave and the wave leaving meet they will creat a standing wave, just for your own info
 
  • #12
well, since its one open end and one close end, its a closed pipe resonator for what it seems. well, an closed pipe resonator has a node at the open end and an antinode at the close end. The shortes column of air that can have that is 1/4 wavelength long. one must use the equation F=n(v/4L) where f is the frequency, n is the number of harmonics it has to be odd numbers though, v is velocity of air, and L is the length. Since you didnt give me what the temperature was then I am going to say that is room temperature in which sound travels at 343 m/s.

so in order to calculate where there will be resonance for a frequency you must change the equation to: L=n(v/4F)
 
  • #13
sebas531 said:
v is velocity of air
sorry about that v is the velocity of sound. I was thinking about the air temperature.
 
  • #14
Thanks for the replies!
I have now only three small questions left I've been wondering about:
Why does the cork dust move in Kundts tube?
When calculating the velocity of sound, why does it differ so much? Is it because I measured bad?
And why does it differ so much from the "ideal" resonance?
 
  • #15
Alec said:
Why does the cork dust move in Kundts tube?

I don't really understand what you are asking. Could you state your question in a different way?

Alec said:
When calculating the velocity of sound, why does it differ so much? Is it because I measured bad?
well, you have not told me how you calculated the speed of sound. Tell me what you did and then I might be able to tell you why.

Alec said:
And why does it differ so much from the "ideal" resonance?
Good question. When i studied sound, i came across a lab that eventhough it varied in process was still about the same subject. Well, when i first did the lab i got really far answers from the accurate ones. I asked myself and my teacher why but we never knew. But i then made some calculations using the formula that i gave you before and when to check resonance again in the lab around those points and i got it really close. sorry but i cannot help you out with these one.
 

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