Why Does Smoke Rise? An Exploration of Physics Principles

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SUMMARY

The discussion centers on the physics principles explaining why smoke rises, particularly during the combustion of paper. It highlights the relationship between temperature, pressure, and density, using the equations \(T^{1.4} P^{-0.4} = const.\) and \(\rho=PM/RT\). When the temperature doubles, the pressure increases by a factor of 11.3, while the density decreases by a factor of 5.7. The key conclusion is that smoke rises because the warm air, which is less dense than the cooler surrounding air, creates an upward flow despite the increased density of the smoke particles.

PREREQUISITES
  • Understanding of ideal gas laws and equations
  • Basic knowledge of thermodynamics, particularly adiabatic processes
  • Familiarity with combustion principles and atmospheric pressure effects
  • Mathematical skills to manipulate equations involving temperature, pressure, and density
NEXT STEPS
  • Study the ideal gas law and its applications in thermodynamics
  • Explore adiabatic processes in greater detail, focusing on real-world examples
  • Research the effects of temperature and pressure on gas behavior in open systems
  • Investigate combustion dynamics and the behavior of gases during combustion
USEFUL FOR

Students of physics, engineers in thermodynamics, and anyone interested in the principles of combustion and fluid dynamics will benefit from this discussion.

jaumzaum
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If we consider that the heating of the products created in the combustion of paper to be an almost adiabatic process (as it's extremely fast), then
$$T^{1.4} P^{-0.4} = const. $$
If we double the temperature, we multiply the pressure by 11.3
The density of an ideal gas is
$$ \rho=PM/RT$$
If we double the temperature, the density would be multiplied by 5.7

So why would the smoke rises if it became more dense?
 
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jaumzaum said:
If we double the temperature, we multiply the pressure by 11.3
How can that be if the combustion isn't happening in an enclosure?
 
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Flame is roughly a steady state process taking place at atmospheric pressure. The smoke particles are carried upward in the warm air which rises because is is less dense than cooler room air.
 
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jaumzaum said:
we multiply the pressure by 11.3
Not if it is an open flame at atmospheric pressure
 
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