Why Does Tension Peak at Geostationary Height in a Space Elevator?

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SUMMARY

The discussion centers on the tension dynamics in a space elevator, particularly at geostationary height. At this height, the weight and centrifugal forces are equal, resulting in maximum tension in the elevator cable. Below geostationary height, tension increases as weight exceeds centrifugal force, while above this height, tension decreases as centrifugal force surpasses weight. The concept of a free-standing tower is introduced, where tension is zero at both ends, peaking at geostationary height.

PREREQUISITES
  • Understanding of gravitational and centrifugal forces
  • Familiarity with the concept of geostationary orbit
  • Basic knowledge of tension in physical structures
  • Ability to interpret equilibrium conditions in physics
NEXT STEPS
  • Study the principles of gravitational force and centrifugal force in detail
  • Research the mechanics of geostationary orbits and their implications on structures
  • Explore the concept of free-standing structures in engineering
  • Examine case studies of tension in cables and their applications in engineering
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Students of physics, engineers involved in structural design, and anyone interested in the mechanics of space elevators and tension dynamics.

Katie1990
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Homework Statement



I am tasked to summarise this paper http://chaos.swarthmore.edu/courses/PDG07/AJP/AJP000125.pdf

I am struggeling to understand the statements of tension at the bottom of the first side namely

For an element at geostationary height that is, at a distance from the Earth’s center equal to the radius of geostationary orbit the weight and centrifugal forces are equal W=FC, and therefore the tension forces at the two ends must also be equal FU=FD for equilibrium. For an element below geostationary height, the weight force W exceeds the centrifugal force FC and one must have FUFD for equilibrium. These two preceding statements imply that the tension in the tower increases with height from ground level to geostationary height. In contrast, for an element above the geostationary height, the centrifugal force FC exceeds the weight W and hence FUFD for equilibrium, implying that the tension in the tower decreases as a function of height past the geostationary height. A free standing tower is one for which
the tension drops to zero at both ends, requiring no restraint at either end to keep the tower in place. The overall picture of a free standing tower is thus of a structure in which the tension rises from zero at ground level to a maximum value at geostationary height, and then decreases to zero again at the upper end.

Homework Equations





The Attempt at a Solution



I can't understand why tension is maximum at geostationary orbit surely the two tensions at this point sum to zero? And shouldn't the tensions at each end be maximum and not zero as stated?
 
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Katie1990 said:
I can't understand why tension is maximum at geostationary orbit surely the two tensions at this point sum to zero? And shouldn't the tensions at each end be maximum and not zero as stated?

Consider a chain hanging from the ceiling with the first link fixed to the ceiling and the final one dangling just above the floor. There are n links, each with a weight of 1 N. What's the tension on the first link? How about the final (dangling) link?
 
I managed to solve this I had forgotten that tension has no direction, I had been cancelling tensions rather then summing them!
 

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