Why Does Term Not Appear in Classical Lagrangian for Spin 1/2 Electrodynamics?

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SUMMARY

The term \(\frac{e}{2} \bar{\Psi} (x) \Sigma^{\mu\nu} F_{\mu\nu}(x) \Psi (x)\) does not appear in the classical Lagrangian for spin 1/2 parity invariant electrodynamics due to its non-renormalizability. This conclusion is supported by arguments found in Weinberg's "Quantum Field Theory" regarding power counting and the implications of the electromagnetic field tensor's derivatives. The discussion highlights the distinction between classical dynamics and quantum field theory, particularly in relation to charged hadrons with anomalous magnetic moments.

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dextercioby
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There's been quite a while since reading some serious physics, so i forgot some key points. The question I'm about to ask may seem trivial for a knowledgeable person, but I can't find the answer and I thought it is easier to get a right answer here, than wondering through a dozen of QFT books.

So here goes:

Why does the term

[tex]\frac{e}{2} \bar{\Psi} (x) \Sigma^{\mu\nu} F_{\mu\nu}(x) \Psi (x)[/tex]

NOT appear in the classical lagrangian for the spin 1/2 parity invariant electrodynamics ?

p.s. I hope the notation is obvous, Sigma is the spin matrix = <i/2> times the commutator of the gamma matrices, the F is the e-m field tensor and the big Psi-s are the Dirac spinors.
 
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There is a couple of reasons; one of them - the theory is non-renormalizable with this term.

If you consider a usual, non secondary quantized Dirac equation, this term is allowed in dynamics of charged hadrons (protons) with an anomalous magnetic moment.
 
I don't know why they got you banned, but can you sustain your <non-renormalizability> reasoning with some article published in a peer-reviewed journal or a book on QFT/QED ?

Thank you.

P.S. This question is, of course, again open to other people as well, since this is (up to moderation) a free forum.

LATE EDIT: Okay, I've seen the argumentation in the first volume of Weinberg's book on QFT. It's due to <power counting> and the nonrenormalizability is induced by the presence of the derivative in the e-m tensor.
 
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