Why Does the Current Halve at This Frequency in an AC Series Circuit?

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SUMMARY

The discussion centers on calculating the frequency at which the current in an AC series circuit with a resistor (R = 12 ohms) and an inductor (L = 4.5 mH) is half its value at zero frequency. The correct formula for frequency is f = sqrt(3R)/(2πL). The initial calculation of 212.21 Hz was identified as incorrect due to an error in the application of the formula. The correct frequency must be derived using the specified values accurately.

PREREQUISITES
  • Understanding of AC circuit theory
  • Familiarity with inductors and resistors
  • Knowledge of RMS values in electrical engineering
  • Proficiency in using mathematical formulas for circuit analysis
NEXT STEPS
  • Review the derivation of the formula f = sqrt(3R)/(2πL)
  • Explore the impact of inductance on AC circuit behavior
  • Learn about RMS values and their significance in AC circuits
  • Investigate the role of frequency in determining current and voltage relationships
USEFUL FOR

Electrical engineering students, circuit designers, and anyone studying AC circuit analysis will benefit from this discussion.

sma235
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Homework Statement



A series circuit contains only a resistor and an inductor. The voltage V of the generator is fixed. If R = 12 ohms and L = 4.5 mH, find the frequency at which the current is one-half its value at zero frequency. Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.


Homework Equations



f=sqrt(3R)/2*pi*L


The Attempt at a Solution



I calculated 212.21 Hz but this was incorrect

 
Physics news on Phys.org
Your equation for the frequency is wrong. How did you get it? ehild
 

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