A Why does the description of a composite system involve a tensor product?

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The description of composite systems involves the tensor product because it mathematically represents the combination of independent quantum states. This concept allows for the construction of multi-particle wave functions as linear combinations of single-particle functions, maintaining the linearity of the system. The tensor product formalizes the relationship between independent spaces and their corresponding unit vectors or kets. It ensures that when one part of the system is traced out, the original state can still be recovered. Understanding this framework is crucial for grasping the behavior of quantum systems.
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Can anyone answer me that why the description of composite system involve tensor product ? Is there any way to realize this intuitively ?
 
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The tensor product is not only used for composite systems, even for a single particle moving in space the 3d base kets are built as a product of 1d kets

$$\left|x,y,z\right\rangle =\left|x\right\rangle \otimes\left|y\right\rangle \otimes\left|z\right\rangle $$

As I see it, the tensor product is an abstract formalization of the following fact: Let ##\psi(x_{1,}x_{2})## be a two-particle wave function and ##{\phi_{n}(x)}## an orthogonal basis of functions for the one particle Hilbert space ##L^{2}## (say, the Hermite polynomials). Then you can write ##\psi(x_{1,}x_{2})## as a linear combination of functions of the form ##\phi_{n}(x_{1})\phi_{m}(x_{2})##. If we write this using an abstract vector, we are basically defining a tensor product.
 
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The tensor product is the mathematical respresentation of two independent spaces, two independent unit vectors/kets or two independent tensors to be viewed as one. The context is linearity, and the tensor product preserves the linearity of both factors in such a way that the restriction to one of both (via the trace over the other) returns the original vector/ket/space/tensor.
 
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For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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