Why does the given conserved quantity mean the motion is on a cone?

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SUMMARY

The conservation of the quantity $$\vec J=\vec r \times\vec p +eg\frac {\vec r}{|\vec r|}$$ in a magnetic field defined by $$B(\vec r)=g \frac {\vec r}{|\vec r|^3}$$ indicates that the motion of an electron is constrained to the surface of a cone. By manipulating the equation $$\vec{r} \cdot \vec{J}=e g r$$ and applying spherical coordinates, it is established that the angle $$\vartheta$$ remains constant, leading to the conclusion that the trajectory forms a cone. The relationship $$\cos \vartheta=\frac{e g}{J}$$ confirms the constancy of the angle, solidifying the conical motion.

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deuteron
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TL;DR Summary: .

An electrone moves in a magnetic field ##B(\vec r)=g \frac {\vec r}{|\vec r|^3}##. Why does the conservation of the quantity $$\vec J=\vec r \times\vec p +eg\frac {\vec r}{|\vec r|}$$ mean that the motion is on the surface of a cone?
 
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You multiplying ##\vec{J}## with ##\vec{r}## gives
$$\vec{r} \cdot \vec{J}=e g r.$$
Now use spherical coordinates with ##\vec{J}/J## as the polar axis. Then the equation implies
$$J x_3 =e g r \; \Rightarrow \; \cos \vartheta=\frac{x_3}{r}=\frac{e g}{J}=\text{const},$$
which is the (implicit equation of a cone).

In the spherical coordinates you thus have
$$\vec{r}=\begin{pmatrix} r \sin \vartheta \cos \varphi \\ r \sin \vartheta \sin \varphi \\ e g r/J \end{pmatrix},$$
which describes a cone since ##\vartheta=\text{const}##.
 
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