Why Does the Integration of exp[abs(x)+3]*delta(x-2) from -1 to 1 Equal Zero?

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SUMMARY

The integral of exp[abs(x)+3]*delta(x-2) from -1 to 1 equals zero because the Dirac delta function, delta(x-2), is only non-zero at x=2, which lies outside the integration limits. Since the integrand is zero for all other points within the interval [-1, 1], the result of the integral is definitively zero. The evaluation of f(2) yields 148.4, but this value does not affect the integral due to the absence of x=2 in the specified domain.

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Homework Statement



Integrate exp[abs(x)+3]*delta(x-2) dx, -1, 1

2. The attempt at a solution

f(x)=exp[abs(x)+3]*delta(x-2)
f(2)=148.4
Integrate exp[abs(x)+3]*delta(x-2) dx, -1, 1 = 0

3. Why is the answer 0?
 
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NeedPhyHelp said:

Homework Statement



Integrate exp[abs(x)+3]*delta(x-2) dx, -1, 1

2. The attempt at a solution

f(x)=exp[abs(x)+3]*delta(x-2)
f(2)=148.4
Integrate exp[abs(x)+3]*delta(x-2) dx, -1, 1 = 0

3. Why is the answer 0?

Because the point x=2 does not lie in your domain of integration and your integrand vanishes at every other point.
 
Note that dirac delta function is zero if its argument is nonzero. The integration interval <-1;1> does not contain point x=2, where the dirac delta function is only nonzero.
 

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