Why Does The Squeeze Theorem Justify Limits Of Upper And Lower Sums?

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SUMMARY

The discussion centers on the application of the Squeeze Theorem in the context of calculating the area under a curve using upper and lower sums. It establishes that as the number of rectangles, n, approaches infinity, the limit of the upper and lower sums converges to the same value, validating the choice of any x-value within the sub-intervals. This is due to the relationship f(mi) ≤ f(xi) ≤ f(Mi), which ensures that the middle sum is effectively squeezed between the minimum and maximum sums, confirming the limit's consistency.

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Bashyboy
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I am currently reading about finding areas under graphs using summations, specifically taking the of the number of rectangles, n, goes to infinity. My books says that "because the same limit value is attained for both minimum value f(mi) and the maximum value f(Mi), it follows from the squeeze theorem that the choice of x in the ith sub-interval does not affect the limit." Why does the squeeze theorem say that I can do this?
 
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I suppose another way of wording my question is why can I choose any x-value in the sub-interval.
 
Because f(mi)≤f(xi)≤f(Mi).

Then summing, the middle sum is squeezed by the other two sums.
 

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