Why Does This Trigonometric Identity Seem Incorrect?

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Homework Help Overview

The discussion revolves around a trigonometric identity involving the expression (sin^2x + 4sinx + 4) / (sinx + 2) and its equivalence to sinx + 2. Participants are exploring the validity of this identity and the implications of factoring the numerator.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to factor the numerator and question the steps involved in simplifying the expression. There are inquiries about the validity of canceling common factors and the conditions under which such operations hold true.

Discussion Status

Several participants have provided guidance on factoring and simplifying the expression. There is an ongoing exploration of the implications of canceling terms and the conditions that affect the validity of such operations. Questions remain about specific values of x that may affect the equality.

Contextual Notes

Participants are discussing the implications of specific values that could lead to undefined expressions, particularly focusing on the denominator and its role in the overall identity.

Veronica_Oles
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Homework Statement


sin^2x + 4sinx +4 / sinx + 2 = sinx +2

Homework Equations

The Attempt at a Solution


L.S = sin^2x + 4sinx +4 / sinx + 2
=1-cos^2+4(sinx + 1) / sinx +2

Not sure where to go from there.
Not sure if I was even supposed to factor out the 4?
 
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Veronica_Oles said:

Homework Statement


sin^2x + 4sinx +4 / sinx + 2 = sinx +2

Homework Equations

The Attempt at a Solution


L.S = sin^2x + 4sinx +4 / sinx + 2
=1-cos^2+4(sinx + 1) / sinx +2

Not sure where to go from there.
Not sure if I was even supposed to factor out the 4?
Please enclose the entirety of any numerator and/or denominator in parentheses.
 
SammyS said:
Please enclose the entirety of any numerator and/or denominator in parentheses.

(Sin^2x + 4sinx + 4) / (sinx + 2) = sinx + 2
 
Veronica_Oles said:
(Sin^2x + 4sinx + 4) / (sinx + 2) = sinx + 2
Factor the numerator.
 
SammyS said:
Factor the numerator.
Thank you, didn't catch that.
 
Veronica_Oles said:
Thank you, didn't catch that.
So, what do you get ?
 
SammyS said:
So, what do you get ?
((Sinx + 2)(Sinx + 2)) / (Sinx + 2)

Then you cancel one from top and bottom to get: Sinx + 2.
 
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Veronica_Oles said:
((Sinx + 2)(Sinx + 2)) / (Sinx + 2)

Then you cancel one from top and bottom to get: Sinx + 2.

Yes, but it is a tiny bit more complicated. Here's something to think about:

1) Why doesn't the following equality hold for all ##x##:

\frac{(x+2)(x+2)}{x+2} = x+2

2) Why is this no problem with the question in the OP?
 
micromass said:
Yes, but it is a tiny bit more complicated. Here's something to think about:

1) Why doesn't the following equality hold for all ##x##:

\frac{(x+2)(x+2)}{x+2} = x+2

2) Why is this no problem with the question in the OP?

((Sinx + 2)(Sinx + 2)) you then take reciprocal of denominator and multiply it by the numerator, and that it is when you cancel them out?
 
  • #10
Can you always divide out common factors from numerator and denumerator? For example, can you always say that (cosx-1)(cosx + 1)/(cosx - 1) = cosx + 1?

Why can/can't you say that? And what about your expression, those are things you have to think about!
 
  • #11
micromass said:
Yes, but it is a tiny bit more complicated. Here's something to think about:

1) Why doesn't the following equality hold for all ##x##:

\frac{(x+2)(x+2)}{x+2} = x+2

2) Why is this no problem with the question in the OP?

To give you a hint, what happens if we plug in -2 for x? Pay attention to the denominator.
 
  • #12
micromass said:
Yes, but it is a tiny bit more complicated. Here's something to think about:

1) Why doesn't the following equality hold for all ##x##:

\frac{(x+2)(x+2)}{x+2} = x+2

2) Why is this no problem with the question in the OP?

Veronica Oles said:
((Sinx + 2)(Sinx + 2)) you then take reciprocal of denominator and multiply it by the numerator, and that it is when you cancel them out?
micromass asked two questions. You didn't respond to his first question, and your answer to the second question doesn't address why ##\frac{(\sin x+2)(\sin x+2)}{\sin x+2} = \sin x+2## is always true, regardless of the value of x.
 

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