Why doesn't my derivation of a product work?

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The discussion centers on the incorrect application of the product rule in calculus, specifically in the context of limits. The user attempts to derive the product of two functions using limits but fails due to the non-convergence of certain limits involved, particularly \lim_{h\rightarrow 0}{\frac{f(x)}{h}}. The correct approach requires that all limits converge, which is not the case in the user's derivation. The established product rule states that \lim_{x\rightarrow a}{f(x)g(x)} = \lim_{x\rightarrow a}{f(x)} \cdot \lim_{x\rightarrow a}{g(x)} only holds under specific conditions.

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georg gill
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What do I do wrong here:[tex]\frac{f(x+h)g(x+h)-f(x)g(x)}{x+h-x}=\frac{f(x+h)g(x+h)}{h}-\frac{f(x)g(x)}{h}=\frac{f(x+h)}{h}g(x+h)-\frac{f(x)}{h}g(x)=\lim_{h \to 0}\frac{f(x+h)}{h}\lim_{h \to 0}g(x+h)-\lim_{h \to 0}\frac{f(x)}{h}g(x)[/tex][tex]\lim_{h \to 0}g(x+h)=g(x)[/tex]
[tex]\lim_{h \to 0}\frac{f(x+h)}{h}\lim_{h \to 0}g(x+h)-\lim_{h \to 0}\frac{f(x)}{h}g(x)=\lim_{h \to 0}\frac{f(x+h)}{h}g(x)-\lim_{h \to 0}\frac{f(x)}{h}g(x)=(\lim_{h \to 0}\frac{f(x+h)}{h}-\lim_{h \to 0}\frac{f(x)}{h})g(x)=(\lim_{h \to 0}\frac{f(x+h)-f(x)}{h})g(x)=\frac{df}{dx}g(x)[/tex]I know how they derieve the derivation of a product:

http://bildr.no/view/918745

But how come what I did above does not work?
 
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You did something like

[tex]\lim_{x\rightarrow a}{f(x)g(x)+h(x)}=\lim_{x\rightarrow a}{f(x)}\lim_{x\rightarrow a}{g(x)}+\lim_{x\rightarrow a}{h(x)}[/tex]

But this is not true. You can't do that.

It is ONLY true if [itex]\lim_{x\rightarrow a}{f(x)}[/itex], [itex]\lim_{x\rightarrow a}{g(x)}[/itex] AND [itex]\lim_{x\rightarrow a}{h(x)}[/itex] converge. In your example, you don't have that. For example

[tex]\lim_{h\rightarrow 0}{\frac{f(x)}{h}}[/tex]

does not converge.
 

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