Why I*ε Cannot be Used to Calculate Power

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In a pure LC circuit, where resistance (R) is zero, no energy or power is absorbed, as inductors and capacitors only store energy rather than dissipate it. Resistance is essential for generating power, as it is the only component that converts electrical energy into heat. The discussion emphasizes that without resistance, the calculation of power using the formula I*ε is not applicable. Inductors and capacitors can store energy but do not contribute to power generation. Therefore, power calculations in pure LC circuits are not valid.
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Homework Statement
In a series RLC circuit the rms value of the generator emf is ε and the rms value of the current is i. The current lags the emf by Φ, The average power suppplied by the generator is given by:

A. (iε/2) cos Φ
B. iε
C. i^2/Z
D.( i^2)Z
E. (i^2)R

ans: E
Relevant Equations
P = IV = I^2R = V^2/R
Why can't we calculate use I*ε to obtain the power?
 
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If it is a pure LC circuit (R=0) (or pure L or pure C) there will be no energy/power absorbed.
 
Keith_McClary said:
If it is a pure LC circuit (R=0) (or pure L or pure C) there will be no energy/power absorbed.
I think I got what you mean, but I would like to double check.
Is it because inductor and capacitor both can store energy while resistance only dissipates energy, and thus resistance is the only electric accessory that can generate power?
 
Keith_McClary said:
@hidemi Right.
Thank you for confirming!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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