Why is a Shorter Spring Stiffer Than a Longer One?

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SUMMARY

The discussion clarifies why shorter springs exhibit greater stiffness compared to longer springs, directly relating to Hooke's Law and the concept of strain. The spring constant (K value) is higher for shorter springs due to their increased strain for the same elongation. The elasticity formula, defined as stress divided by strain, further illustrates that for a constant force, shorter springs experience a greater change in length relative to their original length, resulting in a higher K value. This relationship is crucial for understanding material behavior under stress.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Familiarity with the concepts of stress and strain
  • Knowledge of elasticity and its mathematical representation
  • Basic principles of physics related to forces and materials
NEXT STEPS
  • Study the mathematical derivation of Hooke's Law and its applications
  • Explore the relationship between modulus of elasticity and material stiffness
  • Investigate the effects of different materials on spring behavior
  • Learn about the practical applications of springs in engineering and design
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This discussion is beneficial for physics students, mechanical engineers, and anyone interested in material science and the mechanics of materials.

sweetrose
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a physics question i was assigned was:

If two springs are made of the exact same material, but one is shorter than the other, why is the shorter spring stiffer than the other spring?

I know it is related to Hooke's law being that if a spring has a higher K value, it is stiffer, but I don't understand why the shorter spring's coils wouldn't stretch the same amount as the other spring's coils if the downward force on each spring is the same. So basically, I want to understand why the shorter spring has a higher K value than the longer spring.
 
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What reason do you have for believing that "a shorter spring is stiffer"?
 
It relates to strain - the ratio of elongation to original length. instead of putting it in terms of spring constant, put it in terms of modulus of elasticity (similar but not the same). I'll only use the terms that relate to what you are trying to figure out.

here is the formula for elasticity (NOT the same as spring constant)

elasticity = stress/strain

rearrange it once to get stress

stress = (elasticity)(strain)

Since elasticity is the same for both a long and short spring, I should just leave it out. Stress is actually pressure but since both springs would have the same area, I'll just leave out the area part and make it a force.

F = strain

So now you know the force is dependent on strain, so what is strain? Strain is the change in length divided by the original length.

strain = \frac{\DELTA L}{L_o}

Shorter springs have higher a higher strain for the same amount of elongation and since F (force) is affected by strain, the k value must increase.
 

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