Why is a1 = 2*a2 in a pulley system?

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asi123
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Homework Statement



Hey guys.
I have the following pulley system (in the pic).
I wrote down all the equations.
The thing I don't get is the accelerations equation (a1 = 2*a2). I understand that I can get to this equation somehow by the length of the rope, but how?
Thanks.

Homework Equations





The Attempt at a Solution

 
Attachments
  • Handwritten equations for a pulley system: T2 = 2T1, m2g - T2 = m2a, m2g - 2T1 = m2a2, T1 - m1g sin α = m1a1, and m2g - 2m1g sin α = m2a2 + 2m1a1, ending with a1 = 2a2 boxed. Beside it, a sketch of a block on an incline at angle α joined by rope over a pulley to a hanging pulley carrying mass m2.
    scan0006.jpg
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asi123 said:
The thing I don't get is the accelerations equation (a1 = 2*a2). I understand that I can get to this equation somehow by the length of the rope, but how?

Hi asi123! :smile:

You get it by double-differentiating x1 = 2x2 …

and that is simple geometry … when m2 moves a distance x2, m1 moves a distance x1 = 2x2. :smile: