Why is Acceleration Non-Zero at Maximum Height?

[nebbione]

Hi everyone! If i know that acceleration is the derivative of the velocity, why when i throw an object in the air when the object reaches the maximum height its velocity is 0 m/s and its acceleration is still -9.8 m/s^2 ? I mean, the derivative of 0 m/s is not -g but still 0.

Who can explain me this ?

 

[Vanadium 50]

What is the derivative of y = 4x - 4? What is the derivative of that when x = 1?

 

[nebbione]

the derivative is 4 and when x=1 is still 4.

 

[Vanadium 50]

Do you see your mistake now?

 

[adi1998]

Velocity in this case(magnitude) is not constant.Therefore you have to differentiate velocity as a function of time this and find its value at the required time.However,since velocity increases uniformly and I've is linear,its derivative will be constant

 

[sarsonlarson5]

Vanadium 50 -

Clever - interesting how you explained what he did wrong
without explicitly stating what he did wrong. That is a good
strategy to employ when teaching others. Thank You.