The discussion revolves around the relationship between net force and acceleration, particularly in the context of a truck moving at constant velocity. Participants explore the forces acting on the truck, including gravitational, normal, applied, and frictional forces, and question how these forces balance out to result in zero net force despite the truck's motion.
Participants express differing views on the nature of forces acting on the truck and the conditions under which net force can be considered zero. There is no consensus on the definitions and implications of applied versus frictional forces, and the discussion remains unresolved regarding the clarity of these concepts.
Participants highlight the complexity of defining forces in motion, particularly in relation to reference frames and the influence of external conditions such as incline and friction. There are unresolved questions about the definitions and roles of various forces involved in the scenario.
The sign of work doesn't just depend on the reference frame, but also on whether the value represents work done by A on B, or by B on A. These are two completely different issues, that can affect the sign of work.sophiecentaur said:It's the same with Work By and Work Done. It's just Work with a sign which depends on your measurement frame.
Maybe but they are both viewed in an intuitive way.A.T. said:These are two completely different issues
It's only by knowing the displacement and the force that you can decide what's on what. In a scenario of say two jet engines pushing against each other you can pass through the condition where the net FTD changes sign. Or are you saying that the frame of reference is involved? Perhaps if you made your statement in a different way, I'd understand what your are saying.A.T. said:but also on whether the value represents work done by A on B, or by B on A.
That is no reason to conflate them.sophiecentaur said:Maybe but they are both viewed in an intuitive way.
Yes, from these two you can compute work.sophiecentaur said:It's only by knowing the displacement and the force that you can decide what's on what.
This has been explained to you so many times in previous threads. Just reread them instead of hijacking another one.sophiecentaur said:Perhaps if you made your statement in a different way, I'd understand what your are saying.