Zero acceleration = zero net force?

Click For Summary
SUMMARY

The discussion centers on the concept of net force and acceleration in the context of a truck moving at constant velocity. It is established that when a truck moves with constant velocity, its acceleration is zero, resulting in a net force of zero. The forces acting on the truck, including gravitational force, normal force, and frictional forces, balance out, leading to this state. The applied force from the engine is countered by frictional forces, allowing the truck to maintain constant speed without acceleration.

PREREQUISITES
  • Understanding of Newton's First Law of Motion
  • Familiarity with concepts of force, friction, and acceleration
  • Knowledge of reference frames in physics
  • Basic mechanics of vehicles and propulsion systems
NEXT STEPS
  • Study Newton's Second Law of Motion for deeper insights into force and acceleration relationships
  • Explore the concept of friction in detail, including static and kinetic friction
  • Learn about reference frames and their implications in physics
  • Investigate the mechanics of vehicle propulsion systems and their efficiency
USEFUL FOR

Students of physics, automotive engineers, and anyone interested in understanding the principles of motion and forces in everyday scenarios.

  • #31
sophiecentaur said:
It's the same with Work By and Work Done. It's just Work with a sign which depends on your measurement frame.
The sign of work doesn't just depend on the reference frame, but also on whether the value represents work done by A on B, or by B on A. These are two completely different issues, that can affect the sign of work.
 
  • Like
Likes   Reactions: weirdoguy, berkeman, jbriggs444 and 1 other person
Physics news on Phys.org
  • #32
A.T. said:
These are two completely different issues
Maybe but they are both viewed in an intuitive way.
A.T. said:
but also on whether the value represents work done by A on B, or by B on A.
It's only by knowing the displacement and the force that you can decide what's on what. In a scenario of say two jet engines pushing against each other you can pass through the condition where the net FTD changes sign. Or are you saying that the frame of reference is involved? Perhaps if you made your statement in a different way, I'd understand what your are saying.
 
  • #33
sophiecentaur said:
Maybe but they are both viewed in an intuitive way.
That is no reason to conflate them.
sophiecentaur said:
It's only by knowing the displacement and the force that you can decide what's on what.
Yes, from these two you can compute work.
sophiecentaur said:
Perhaps if you made your statement in a different way, I'd understand what your are saying.
This has been explained to you so many times in previous threads. Just reread them instead of hijacking another one.
 
  • Like
Likes   Reactions: weirdoguy, berkeman, SammyS and 1 other person
  • #34
This thread has run its course, and after some editing it has been closed. Thanks to all who tried to offer clear explanations.
 
  • Like
Likes   Reactions: paulb203 and jedishrfu

Similar threads

  • · Replies 41 ·
2
Replies
41
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 29 ·
Replies
29
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
903
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 13 ·
Replies
13
Views
629
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K